You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
A-2b=-10
b=-10-a.
Hope this is the answer
Mark as brainliest
Answer:
D 90
Step-by-step explanation:
x/4 ≥ 20
Multiply each side by 4
4*x/4 ≥ 20*4
x ≥ 80
The only number greater than or equal to 80 is 90
Answer: y varies directly as x ", " y varies proportionally as x ", or " y is directly proportional to x . ") This means that as x increases, y increases and as x decreases, y decreases—and that the ratio between them always stays the same.
Step-by-step explanation:
Answer: 3 3/4 is the answer :)
