Question

Nature of roots of 4x²-4x-19=0​

Answer 1

Answer:

The roots are real.

Step-by-step explanation:

Given quadratic equation to us is 4x² -4x -19 = 0.

With respect to Standard form ax² +bx +c = 0 , Discriminant of the quadratic equation is given by b² - 4ac . Here's a table for Nature of Roots .

$\boxed{\begin{array}{|r|r|r|} \underline{\red{\bf S.no.}} & \underline{\red{\bf Condition }} & \underline{\red{\bf Nature \ of \ Roots }} \\\\ \sf 1 & \sf Discriminant > 0 & \sf Real \:Roots \\\\ \sf 2 &\sf Discriminant = 0 &\sf Equal \:Roots \\\\ \sf 3 & \sf Discriminant < 0 &\sf Complex \: Roots \end{array} }$

Hence here , wrt Standard form ,

• a = 4 , • b = -4 & •c = -19 .

$\implies Discriminant = b^2-4ac \\\\\implies Discriminant = (-4)^2-4(4)(-19) \\\\\implies Discriminant = 16+304 \\\\\boxed{\red{\bf \implies Discriminant = 320 }}$

Hence since Discriminant is Greater than 0 , hence the nature of roots of the quadratic equation is real.