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Lelu [443]
3 years ago
14

Lin rode her bike 2 miles in 8 minutes. She rode at a constant speed. Complete the table to show the distance traveled in 1 minu

te at this speed
Mathematics
2 answers:
sasho [114]3 years ago
6 0
Quarter mile, means she gets 1 mile every 4 minutes, there’s 4 quarters when it comes to every 1 minute, so every minute is a quarter mile
just olya [345]3 years ago
4 0

Answer:

4 miles in 1 min

Step-by-step explanation:

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27

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2x+2=52

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#1 #2 #3 & #4 thank you
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I only (sort of) know 3 and 4

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Divide 10 by 5, the multiply q by the result
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In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
Julli [10]

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0.071,1.928

Step-by-step explanation:

                                                Downtown Store   North Mall Store

Sample size   n                             25                        20

Sample mean \bar{x}                         $9                        $8

Sample standard deviation  s       $2                        $1

n_1=25\\n_2=20

\bar{x_1}=9\\ \bar{x_2}=8

s_1=2\\s_2=1

x_1-x_2=9-8=1

Standard error of difference of means = \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}

Standard error of difference of means = \sqrt{\frac{2^2}{25}+\frac{1^2}{20}}

Standard error of difference of means = 0.458

Degree of freedom = \frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}

Degree of freedom = \frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = (x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)

Confidence interval = 1-(2.0280)\times 0.458,1+(2.0280)\times 0.458

Confidence interval = 0.071,1.928

Hence Option A is true

Confidence interval is  0.071,1.928

4 0
2 years ago
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