The answer for thi question is 2
Answer:
320 cubic feet
Step-by-step explanation:
The volume is proportional to the product of the area of the base and the height of the pyramid. When the dimensions of the base are doubled, the area is multiplied by 2² = 4, hence the volume of the pyramid will be multiplied by 4.
4 × (80 ft³) = 320 ft³
The new volume of the pyramid is 320 cubic feet.
The attached image completes the question.
Answer:
- The part (0, 12000) is constant and the slope is zero
- The part (12000, 38000) is decreasing and slope is negative 0.26.
Step-by-step explanation:
Checking the given graph, we see that
For x = 0 to x = 12,000, the values of y are unchanged. For this, we say it is constant.
The slope here is: 0.85 - 0.85 = 0
For x = 12,000 to x = 38,000, the values of y are decreasing. For this, we say it is negative.
The slope here is: 0.59 - 0.85 = -0.26.
Fewer indicates subtraction and product means multiplication.
4n - 15
Answer: The hook would be 2.2 inches (approximately) above the top of the frame
Step-by-step explanation: Please refer to the picture attached for further details.
The top of the picture frame has been given as 9 inches and a 10 inch ribbon has been attached in order to hang it on a wall. The ribbon at the point of being hung up would be divided into 5 inches on either side (as shown in the picture). The line from the tip/hook down to the frame would divide the length of the frame into two equal lengths, that is 4.5 inches on either side of the hook. This would effectively give us two similar right angled triangles with sides 5 inches, 4.5 inches and a third side yet unknown. That third side is the distance from the hook to the top of the frame. The distance is calculated by using the Pythagoras theorem which states as follows;
AC^2 = AB^2 + BC^2
Where AC is the hypotenuse (longest side) and AB and BC are the other two sides
5^2 = 4.5^2 + BC^2
25 = 20.25 + BC^2
Subtract 20.25 from both sides of the equation
4.75 = BC^2
Add the square root sign to both sides of the equation
2.1794 = BC
Rounded up to the nearest tenth, the distance from the hook to the top of the frame will be 2.2 inches