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2 years ago

1. Jan spends part of her year as a member of a

Mathematics

1 answer:

antiseptic1488 [7]2 years ago

3 0

Answer:

13 months in a half......

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Write the equation of the line parallel to y=4 that passes through (1,6)

nadya68 [22]

Answer:

y=0x+6

Step-by-step explanation:

6 0

3 years ago

Which equation shows how to determine the volume of the dollhouse?

777dan777 [17]

Answer:

first choice

Step-by-step explanation:

The volume of a rectangular prism is L*H*B.

So the volume of the rectangular prism pictured here is 24*10*8

The volume of a triangle prism is 1/2 *H*L*B.

So the volume of the triangle prism pictured here is 1/2 *6*24*8

The volume of the whole figure is the sum of the volume of the rectangular prism and volume of the triangular prism which is in this case:

24*10*8 + 1/2 *6*24*8.

Answer is the first choice.

(It wouldn't be third because 10 has nothing to with the triangular prism part)

7 0

3 years ago

Find the product of (x + 3)(x - 3)

Roman55 [17]

Answer:

(x+3)(x-3) is x²-9

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Someone help please want it asap anyone??

Gre4nikov [31]

Answer:

Pretty sure it's the last one at the bottom.

8 0

2 years ago

Read 2 more answers

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

2 years ago