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Luda [366]
3 years ago
13

1. Jan spends part of her year as a member of a

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:

13 months in a half......

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-3 5/12 divided 2 please help
finlep [7]

Answer:

on the file:

:)

8 0
3 years ago
4. Use the distributive property to simplify : 12(2−6).
olasank [31]

Answer:

-48

Step-by-step explanation:

12 x 2=24

12 x 6= 72

24 - 72 = -48

7 0
3 years ago
How to prove this using trig identities?
Pavlova-9 [17]

Step-by-step explanation:

tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)

 

                      = (sin2B + cos2B)/[(cosB)(sinB)]

 

                       = 1/[(cosB)(sinB)]

 

                        = (1/cosB)(1/sinB)

 

                        = (secB)(cscB)

7 0
3 years ago
A figure is shown with parallel lines a and b. What is the measure, in degrees, of ∠r?
Novay_Z [31]

Answer:

42 degrees

Step-by-step explanation:

48 and r are equal.

The box means right angle, or 90 degrees

180-90-48=42 degrees

3 0
3 years ago
Read 2 more answers
The amount of polonium-210 remaining, p(t), after t days in a sample can be modeled by the exponential function p(t) = 100e−0.00
Archy [21]

Answer:

% Po lost = 100[1 - e^(-0.005t)]  %; 73.0 g

Step-by-step explanation:

p(t) = 100e^(-0.005t)

Initial amount:        p(0) = 100

Amount remaining: p(t) = 100e^(-0.005t)

Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]

% of Po lost  = amount lost/initial amount × 100 %

= [1 - e^(-0.005t)]  × 100 % = 100[1 - e^(-0.005t)]  %

p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g

The mass of polonium remaining after 63 days is 73 g.

4 0
3 years ago
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