1. Jan spends part of her year as a member of a

Suppose that, in the past, 40% of all adults favored capital punishment. Do we have reason to believe that the proportion of adu

Alex_Xolod [135]

Answer:

The p-value of the test is 0.1469 > 0.05, which means that there is no reason to believe that the proportion of adults favoring capital punishment today has increased, using a 0.05 level of significance.

Step-by-step explanation:

Suppose that, in the past, 40% of all adults favored capital punishment. Test if the proportion has increased:

At the null hypothesis, we test if the proportion is still of 40%, that is:

$H_0: p = 0.4$

At the alternative hypothesis, we test if the proportion has increased, that is, is greater than 40%, so:

$H_1: p > 0.4$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that $\mu = 0.4, \sigma = \sqrt{0.4*0.6}$

Random sample of 15 adults, 8 favor capital punishment.

This means that $n = 15, X = \frac{8}{15} = 0.5333$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.5333 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{15}}}$

$z = 1.05$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion of 0.5333 or more, which is 1 subtracted by the p-value of z = 1.05.

Looking at the z-table, z = 1.05 has a p-value of 0.8531.

1 - 0.8531 = 0.1469.

The p-value of the test is 0.1469 > 0.05, which means that there is no reason to believe that the proportion of adults favoring capital punishment today has increased, using a 0.05 level of significance.

3 0

2 years ago

The dollar value v(t) of a certain car model that is t years old is given by the following exponential function.

dimaraw [331]

Answer:

v(0) = 32,000 . . . dollars

v(13) = 16,427 . . . dollars

Step-by-step explanation:

The initial value is the value of the function for t=0. Put that into the formula and evaluate.

v(0) = 32,000(0.95^0) = 32,000 . . . . dollars

__

The value after 13 years is the function value for t=13. Put that into the formula and evaluate.

v(13) = 32,000(0.95^13) ≈ 32,000·0.513342 ≈ 16,427 . . . . dollars

5 0

3 years ago

The customers at the bank would like to withdraw money from the automated teller machine. Help them enter their personal ID numb

vlabodo [156]

To withdraw money from the automated teller machine the numeric pattern required to complete the personal ID numbers is 2, 13, 24, 35,46,57,68.

As given in the question,

Using automated teller machine customers at the bank withdraw money

Numeric pattern given for the personal ID numbers is

2, 13, 24, 35

First term 'a'= 2

Common difference between consecutive terms are same

'd'=13 -2

=11

It is an arithmetic progression series

nth term = a+ (n-1)d

5th term = 2 +(5-1)11

=46

6th term =2+(6 -1)11

=57

7th term= 2+ (7-1)11

= 68

Therefore, to withdraw money from the automated teller machine the numeric pattern required to complete the personal ID numbers is 2, 13, 24, 35,46,57,68.

The complete question is:

The customers at the bank would like to withdraw money from the automated teller machine. Help them enter their personal ID numbers by completing the numeric patterns. 2, 13, 24, 35, ___, ___, ____.

Learn more about pattern here

brainly.com/question/14720576

#SPJ1

7 0

1 year ago

In what time the compound amount of Rs 60000 at 10% rate is rs 79860?

Ksenya-84 [330]

Answer:

P= Rs 60000

A= Rs 79860

T=1 & 1/2 year = 3/2 years

= 3/2 x 2 = 3 half years

R= ?

Applying the formula A= P (1+r/100)^T

79860 = 60000 (1+ r/100)^3

79860/60000 = (1+r/100)^3

1331/1000 = (1+r/100)^3

root(3)(1331/1000) = (1+r/100)

11/10 = 1+r/100

11/10 -1 = r/100

1/10 = r/100

r= 10 %

Step-by-step explanation:

8 0

3 years ago

The legend on a map states that

dimulka [17.4K]

Answer:

Step-by-step explanation:

1 cm=10 km

8 cm=10×8=80 km

4 0

3 years ago