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3 years ago

Which statement is true regarding the functions on the graph

Mathematics

1 answer:

vaieri [72.5K]3 years ago

6 0

Answer:

Its A

2021 on edge

Step-by-step explanation:

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Solve for x 7 x + 15 equals 38

Galina-37 [17]

Answer:

x = 23/7

Step-by-step explanation:

7 x + 15 equals 38

7x+15 = 38

Subtract 15 from each side

7x+15-15 = 38-15

7x = 23

Divide each side by 7

7x/7 = 23/7

x = 23/7

6 0

4 years ago

Read 2 more answers

HELP ASAP PLEASE<br><br><br> Solve for x -3/4 (x + 2) = 6

igomit [66]

Answer:

Step-by-step explanation:

7 0

3 years ago

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Oblems

nalin [4]

Answer:

$\overline{BC} \cong \overline{DC}$ because corresponding parts of congruent triangles ΔACD and ΔACB are Congruent

Step-by-step explanation:

Statements, Reason

$\overline{AC}$ bisects ∠BCD, Given

$\overline{DC} \perp \overline{AD}$ Given

∠CDA ≅ ∠CBA Right angles are ≅

$\overline{AC} \cong \overline{AC}$ Reflexive property

ΔACD ≅ ΔACB Hypotenuse Leg (HL) congrurency

$\overline{BC} \cong \overline{DC}$ CPCTC

Where:

CPCTC = Corresponding parts of Congruent Triangles are Congruent

⊥ = Perpendicular to

≅ = Congruent

∠ = Angle

Δ = Triangle.

3 0

3 years ago

The velocity of an automobile starting from rest is given by the equation below, where v is measured in feet per second and t is

maria [59]

Answer:

a. At t = 5 s

$a(5)=\frac{1785}{\left(6(5)+17\right)^2}=\frac{1785}{2209}\approx0.808 \frac{ft}{s^2}$

b. At t = 10 s

$a(10)=\frac{1785}{\left(6(10)+17\right)^2}=\frac{255}{847}\approx0.301 \frac{ft}{s^2}$

c. At t = 20 s

$a(20)=\frac{1785}{\left(6(20)+17\right)^2}=\frac{1785}{18769}\approx0.095 \frac{ft}{s^2}$

Step-by-step explanation:

We know that the velocity function is given by

$v(t)=\frac{105t}{6t+17}$

Acceleration is the rate of change of velocity so we take the derivative of the velocity function with respect to time.

$a(t)=\frac{dv}{dt}=\frac{d}{dt} (\frac{105t}{6t+17})$

$\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\105\frac{d}{dt}\left(\frac{t}{6t+17}\right)\\\\\mathrm{Apply\:the\:Quotient\:Rule}:\quad \frac{d}{{dx}}\left( {\frac{{f\left( x \right)}}{{g\left( x \right)}}} \right) = \frac{{\frac{d}{{dx}}f\left( x \right)g\left( x \right) - f\left( x \right)\frac{d}{{dx}}g\left( x \right)}}{{g^2 \left( x \right)}}$

$105\cdot \frac{\frac{d}{dt}\left(t\right)\left(6t+17\right)-\frac{d}{dt}\left(6t+17\right)t}{\left(6t+17\right)^2}\\\\105\cdot \frac{1\cdot \left(6t+17\right)-6t}{\left(6t+17\right)^2}\\\\a(t)=\frac{1785}{\left(6t+17\right)^2}$

a. At t = 5 s

$a(5)=\frac{1785}{\left(6(5)+17\right)^2}=\frac{1785}{2209}\approx0.808 \frac{ft}{s^2}$

b. At t = 10 s

$a(10)=\frac{1785}{\left(6(10)+17\right)^2}=\frac{255}{847}\approx0.301 \frac{ft}{s^2}$

c. At t = 20 s

$a(20)=\frac{1785}{\left(6(20)+17\right)^2}=\frac{1785}{18769}\approx0.095 \frac{ft}{s^2}$

3 0

4 years ago

What is the approximate circumstances of the circle shown below?

dangina [55]

Answer:

the answer to this is D) 61.2

5 0

3 years ago