Can someone please help? This is difficult.
1 answer:
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Answer:
Step-by-step explanation:
Given the logarithm function
For logarithmic equations, is equivalent to
such that
and
In current case:
Substituting the values of and
into the equation
Make into matrix
![\left[\begin{array}{ccc}2&1&1\\1&-3&-1\\4&5&2\end{array}\right] = \left[\begin{array}{ccc}-2\\14\\-4\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%261%261%5C%5C1%26-3%26-1%5C%5C4%265%262%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%5C%5C14%5C%5C-4%5Cend%7Barray%7D%5Cright%5D%20%20%20)
accoring to cramer's rule
replace the y collum with eh constant collumn and find the detterminant
![\left[\begin{array}{ccc}2&-2&1\\1&-14&-1\\4&-4&2\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-2%261%5C%5C1%26-14%26-1%5C%5C4%26-4%262%5Cend%7Barray%7D%5Cright%5D)
det
![2 \left[\begin{array}{ccc}14&-1\\-4&2\end{array}\right]-(-2) \left[\begin{array}{ccc}1&-1\\4&2\end{array}\right]+1 \left[\begin{array}{ccc}1&14\\4&-4\end{array}\right] ](https://tex.z-dn.net/?f=%202%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D14%26-1%5C%5C-4%262%5Cend%7Barray%7D%5Cright%5D-%28-2%29%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-1%5C%5C4%262%5Cend%7Barray%7D%5Cright%5D%2B1%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2614%5C%5C4%26-4%5Cend%7Barray%7D%5Cright%5D%20%0A%0A)
dunno wat fraction is
pick last option
accoring to cramer's rule
replace the y collum with eh constant collumn and find the detterminant
det
dunno wat fraction is
pick last option