He had to put $65 bc. he had to balance his account then added $25
Let
<span>A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)
step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm
step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm
step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm
step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm
step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD
step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and
AB and AD are perpendicular
BC and CD are perpendicular
therefore
the shape is a square wit length side √18 cm
area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²
the answer is18 cm²see the attached figure
Answer: £ 81.38
Step-by-step explanation:
Given: On Monday,
5 builders took
hours ( i.e.
hours ) to build a wall.
On Tuesday, only 2 builders were available.
As workers are inversely proportional to the time if the job remains constant.
Inverse variation equation : 
Let x be the time taken by 2 builders, then


So, 2 builders will take 8.75 hours.
Each paid £9.30 for each hour.
Then, each builder will be paid for the work completed on Tuesday = £9.30 x 8.75
≈ £ 81.38
Hence, each builder will be paid £ 81.38 for the work completed on Tuesday .
Step-by-step explanation:
(a)90 by 10%
90+10% of 90=90(1+0.1)=99
(b)60 by 25%
60(1+0.25)=75
(c)80 by 75%
80(1+0.75)=140
(e)110 by 60%
110(1+0.6)=176
(f)480 by 115%
480(1+1.15)=1032
(g)140 by 45%
140(1+0.45)=203
-5=s/18
Pretend that s/18 is 1/18s
-5=1/18s
Multiply by 18/1 for both sides
-5(18/1)=1/18(18/1)s
Cross out 1 and 1, divide by 1 and then is one.
Cross out 18 and 18, divide by 18 and then is one.
s=-90
Answer: s=-90