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Aleks [24]
3 years ago
7

Awnser please :((((((((((((((((((((

Mathematics
1 answer:
vfiekz [6]3 years ago
3 0

Answer:

I believe it is: 6n+8+7y+4m

Step-by-step explanation:

You can't do anything about the numbers with variables afterwards, so you just list those and you just add and subtract the numbers without variables.  Since the top and bottom are the same, you just list it once.  Sorry, not the best explanation.  Please let me know if I am wrong.  It's been a while since I had to any type of algebra.

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Area of the base= 324cm square , Height=8cm. Find the volume of the cylinder.​
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2592cm^3
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Y² + 4x - 20 - 2y = -x²
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What we have to find in this question

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Read 2 more answers
The average daily high temperature in June in LA is 77 degree F with a standard deviation of 5 degree F. Suppose that the temper
olasank [31]

Answer:

11.51% probability of observing an 83 degree F temperature or higher LA during a randomly chosen day in June

The coldest 10% of the days during June in LA have high temperatures of 70.6F or lower.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 77, \sigma = 5

What is the probability of observing an 83 degree F temperature or higher LA during a randomly chosen day in June?

This probability is 1 subtracted by the pvalue of Z when X = 83. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{83 - 77}{5}

Z = 1.2

Z = 1.2 has a pvalue of 0.8849.

1 - 0.8849 = 0.1151

11.51% probability of observing an 83 degree F temperature or higher LA during a randomly chosen day in June

How cold are the coldest 10% of the days during June in LA?

High temperatures of X or lower, in which X is found when Z has a pvalue of 0.1, so whn Z = -1.28

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 77}{5}

X - 77 = -1.28*5

X = 70.6

The coldest 10% of the days during June in LA have high temperatures of 70.6F or lower.

5 0
3 years ago
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