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juin [17]
3 years ago
12

I will give brainiest

Mathematics
1 answer:
forsale [732]3 years ago
7 0

Answer:

A is equal to <em>20.</em>

Step-by-step explanation:

To find the missing side we have to square both 21 and 29.

 Because 21 x 21 = 441, and 29 x 29 = 841, all we have to do is subtract 841 from 441 and we have 400.

 Now we have to find the square root of 400, since 20 x 20 = 400, that means 20 is our answer.

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Step-by-step explanation:

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The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am
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Step-by-step walkthrough:

a.

Well a standard half-life equation looks like this.

N = N_0 * (\frac{1}{2})^{t/p

N_0 is the starting amount of parent element.

N is the end amount of parent element

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We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

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b.

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2}  =  37g

c.

Now we just gotta do some algebra. Use the original function but this time, replace N(t) with 10g and solve algebraically.

10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}

Take the log of both sides.

log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})

Use the exponent rule for log laws that, log(b^x) = x*log(b)

log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})

\frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = \frac{t}{2.8days}

2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = t

slap that in your calculator and you get

t = 8.1 days

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Step-by-step explanation:

???

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