Question

(-3,2) and ( 2,13) slope interept equation

Answer 1

Given:

The points are (-3, 2) and (2, -13).

To find:

Slope-intercept form of the equation.

Solution:

Here $x_1=-3, y_1=2, x_2=2, y_2=-13$.

Slope of the line:

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-13-2}{2-(-3)}$

$m=\frac{-15}{5}$

m = -3

Using point-slope formula:

$y-y_1=m(x-x_1)$

$y-2=-3(x-(-3))$

$y-2=-3(x+3)$

$y-2=-3x-9$

Add 2 on both sides.

$y-2+2=-3x-9+2$

$y=-3x-7$

Slope-intercept form of the equation is y = -3x - 7.