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2 years ago

14

(-3,2) and ( 2,13) slope interept equation

1 answer:

Svetllana [295]2 years ago

7 0

Given:

The points are (-3, 2) and (2, -13).

To find:

Slope-intercept form of the equation.

Solution:

Here $x_1=-3, y_1=2, x_2=2, y_2=-13$ .

Slope of the line:

$$m=\frac{y_2-y_1}{x_2-x_1}$

$$m=\frac{-13-2}{2-(-3)}$

$$m=\frac{-15}{5}$

m = -3

Using point-slope formula:

$y-y_1=m(x-x_1)$

$y-2=-3(x-(-3))$

$y-2=-3(x+3)$

$y-2=-3x-9$

Add 2 on both sides.

$y-2+2=-3x-9+2$

$y=-3x-7$

Slope-intercept form of the equation is y = -3x - 7.

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or

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and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

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A lot is in the shape of a triangle. One side is 100 ft longer than the shortest side, while the third side is 700 ft longer tha

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We have the next information

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y= the second side measure

y=x+100

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$P=x+y+z$ $2900=x+x+100+x+700$

we sum like terms

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then we isolate the x

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1 year ago

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Answer:

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s = u·t + 1/2·a·t²

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Given that all planes will start motion from rest, we have;

u = 0 m/s

Therefore;

s = 0 × 35 + 1/2 × 3.3 × 35² = 2021.25 meters

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