<span>Simplifying
4x2 + -24x + 4y2 + 72y = 76
Reorder the terms:
-24x + 4x2 + 72y + 4y2 = 76
Solving
-24x + 4x2 + 72y + 4y2 = 76
Solving for variable 'x'.
Reorder the terms:
-76 + -24x + 4x2 + 72y + 4y2 = 76 + -76
Combine like terms: 76 + -76 = 0
-76 + -24x + 4x2 + 72y + 4y2 = 0
Factor out the Greatest Common Factor (GCF), '4'.
4(-19 + -6x + x2 + 18y + y2) = 0
Ignore the factor 4.
</span><span>Subproblem 1
Set the factor '(-19 + -6x + x2 + 18y + y2)' equal to zero and attempt to solve:
Simplifying
-19 + -6x + x2 + 18y + y2 = 0
Solving
-19 + -6x + x2 + 18y + y2 = 0
The solution to this equation could not be determined.
This subproblem is being ignored because a solution could not be determined.
The solution to this equation could not be determined.</span>
Answer:
linear and non-proportional
Step-by-step explanation:
When the same amount is added each week, the relationship is linear. When the initial value is 50, not zero, the relationship is non-proportional.
This is a binomial probability situation, since a dog either is adopted or is not adopted. The chances of a dog's being adopted in 0.20. Here we're speaking of 9 visits. Thus, n=9, p=0.20.
One way of doing this problem is to calculate the probability that ONE dog will be adopted, and then that that TWO dogs will be adopted, and so on, up to NINE dogs. Add together these nine probabilities to get your answer.
But a better (faster) approach would be to calculate the probability that ZERO dogs will be adopted, and then to subtract this from 1.000.
Using my TI-84Plus calculator, I figured that P(0 dogs will be adopted) is binompdf(9,0.20,0), or 0.134. Subtracting this from 1.000, we get 0.866 (answer to this problem).
Answer:
b
Step-by-step explanation: