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4 years ago

A drum of oil has a height of 4 ft and a radius of 1.2 ft. The oil cost $22 per ft³.

1 answer:

iogann1982 [59]4 years ago

3 0

Volume of a Cylinder (Drum) = πr²h

Substitute the known values,
v = 3.14 * (1.2)² * 4
v = 18.09 Ft³

Now, price for 1 Ft³ = $22
So, for 18.09 Ft³ would be: 22 * 18.09 = $397.9

In short, Your Answer would be: $397.9

Hope this helps!

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What is the value of x in the equation 13 x minus 2 (8 + 5 x) = 12 minus 11 x?

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Answer:

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Step-by-step explanation:

Step 1: Convert words into an expression

What is the value of x in the equation 13 x minus 2 (8 + 5 x) = 12 minus 11 x?

13x - 2(8 + 5x) = 12 - 11x

Step 2: Distribute

13x - 2(8 + 5x) = 12 - 11x

13x - 16 - 10x = 12 - 11x

Step 3: Solve for x

13x - 16 - 10x + 11x + 16 = 12 - 11x + 11x + 16

14x / 14 = 28 / 14

x = 2

Answer: x = 2

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For the function given state the period f(t) =6sin(3t-pi/6)-1

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$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

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