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3 years ago

14

Trejon rides his bike 27 miles each day. Which equation can be used to find r, the number of miles he will ride in 8 days? 24 r

Total Miles Ridden 21 21 21 21 21 21 21 21 O A 21 = 1 = 8 O B. 8 xr= 21 OC. 21 : 8=r O D. 8 x 24 = 1

1 answer:

Leona [35]3 years ago

3 0

Answer:

yes I know what I mean to you can be the next rikage to get out there nationalityand and get a doberman baby driver and the Mather family and the kids will have a great weekend in my room to get to know that they are very good friends or not to see my father did it for the first round and

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point I is on line segment HJ. GIVEN IJ = 3× + 3, HI = 3× - 1, and HJ = 3× + 8, determine the numerical length of HJ.

Vedmedyk [2.9K]

Given, IJ = 3x + 3, HI = 3x - 1, and HJ = 3x + 8.

Since I is a point on line segment HJ, we can write

$HJ=HI+IJ$ $\begin{gathered} 3x+8=(3x-1)+(3x+3) \\ 3x+8=6x+2 \\ 8-2=6x-3x \\ 6=3x \\ 2=x \end{gathered}$

Put x=2 in HJ=3x+8.

$\begin{gathered} HJ=3\times2+8 \\ HJ=6+8 \\ =14 \end{gathered}$

Therefore, the numerical length of HJ is 14.

4 0

11 months ago

At 5.45p.M .,lixin,khairul and Devil are at the starting point of a 1-km circular path. Lixin Takes 18 minutes to walk one round

sweet [91]

Answer:

$Meeting\ Time = 6:03\ pm$

Step-by-step explanation:

Given

$Start\ Time= 5:45pm$

$Lixin = 18\ min/round$

$Khairul = 360\ seconds/round$

$Devi = 4minutes/2\ rounds$

Required

Determine their next meeting time

First, we need to get their unit rate in minutes per round

$Lixin = 18\ min/round$

$Khairul = 360\ seconds/round$

Convert 360 seconds to minutes

$Khairul = \frac{360}{60} min/round$

$Khairul = 6 min/round$

$Devi = 4minutes/2\ rounds$

Divide by 2/2

$Devi = 2mins/round$

So, we have:

$Lixin = 18\ min/round$

$Khairul = 6 min/round$

$Devi = 2mins/round$

Next, is to determine the LCM of 18, 6 and 2

$18=2 * 3 * 3$

$6 = 2 * 3$

$3 = 3$

Their LCM is:

$LCM = 2 * 3 * 3$

$LCM = 18$

This means that they will meet 18 minutes after their initial time of departure.

So:

$Meeting\ Time = 5:45\ pm + 18\ minutes$

$Meeting\ Time = 6:03\ pm$

3 0

2 years ago

Seriously need help!!????

Serga [27]

50 would be a good choice of answer

3 0

2 years ago

Solve the system algebraically. Check your work.

Luden [163]

answer.

Answer:

x=2 and y=0 is the required result.

Step-by-step explanation:

We have been given system of equations:

5x+2y=105x+2y=10 (1)

And 3x+2y=63x+2y=6 (2)

We will use elimination method:

Multiply 1st equation by 3 and 2nd equation by 5 we get:

15x+6y=3015x+6y=30 (3)

15x+10y=3015x+10y=30 (4)

Now subtract (4) from (3) we get:

-4y=0−4y=0

y=0y=0

Now, put y=0 in (1) equation:

5x+2(0)=105x+2(0)=10

5x=105x=10

x=2x=2

Hence, x=2 and y=0

8 0

3 years ago

A rectangle with a length of L and a width of W has a diagonal of 10 inches. Express the perimeter P of the rectangle as a funct

KatRina [158]

<h2>Answer:</h2>

The expression which represents the perimeter P of the rectangle as a function of L is:

$Perimeter=2(L+\sqrt{100-L^2})$

<h2>Step-by-step explanation:</h2>

The length and width of a rectangle are denoted by L and W respectively.

Also the diagonal of a rectangle is: 10 inches.

We know that the diagonal of a rectangle in terms of L and W are given by:

$10=\sqrt{L^2+W^2}$

( Since, the diagonal of a rectangle act as a hypotenuse of the right angled triangle and we use the Pythagorean Theorem )

Hence, we have:

$10^2=L^2+W^2\\\\i.e.\\\\W^2=100-L^2\\\\W=\pm \sqrt{100-L^2}$

But we know that width can't be negative. It has to be greater than 0.

Hence, we have:

$W=\sqrt{100-L^2}$

Now, we know that the Perimeter of a rectangle is given by:

$Perimeter=2(L+W)$

Here we have:

$Perimeter=2(L+\sqrt{100-L^2})$

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3 years ago