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3 years ago

In what phase of meiosis are tetrads pulled to opposite poles of the cell?

Biology

1 answer:

VikaD [51]3 years ago

7 0

Answer:

Anaphase I

Explanation:

In anaphase I, the homologous chromosomes are pulled apart and move to opposite poles.

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John rode his bike for 30 miles in 2 hours how fast was he traveling

omeli [17]

Answer:15 miles per hour

Explanation:in 2 hours he moved 30 miles so just get the half of it

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4 years ago

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What is the answer to this!?

MrMuchimi

Answer:

6.82 kg

Explanation:

Step 1: Find conversion

2.20 lb = 1 kg

Step 2: Use Dimensional Analysis

$15.0 \hspace{2} lb(\frac{1 \hspace{2} kg}{2.20 \hspace{2} lb} )$ = 6.81818 kg

Step 3: Simplify

3 sig figs

6.81818 kg ≈ 6.82 kg

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3 years ago

The two main components of the integument are the:

Natalka [10]

The epidermis and the dermis

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4 years ago

Beets are red. what color is being reflected from the beets?

Stells [14]

Answer:

Red because that's the color we see.

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3 years ago

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10. Write the 2 Hardy-Weinberg equations. Use the equation to calculate the percentage of carriers of cystic fibrosis (a recessi

Firlakuza [10]

Using the Hardy-Weinberg equations, the percentage of carriers of cystic fibrosis is 8.19%.

<h3>What are the Hardy-Weinberg equations?</h3>

The Hardy-Weinberg equations describe the relationship between alleles in a population that is fairly constant.

The Hardy-Weinberg equations are given below as;

$p^{2} + 2pq + q^{2} = 1 \\p + q = 1$

$q^{2} = 0.009\\q = 0.09\\p = 1 - 0.09\\p = 0.91$ Hardy-Weinberg equations

Percentage of carriers = 2pq

Percentage of carriers = 2 * 0.09 * 0.91 * 100 = 8.19%

Therefore, the percentage of carriers of cystic fibrosis is 8.19%.

Learn more about Hardy-Weinberg equations at: brainly.com/question/16039271

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2 years ago