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Ivanshal [37]
3 years ago
12

A group of small fish live in a lake with a uniformly light-brown sandy bottom. Most of the fish are light brown, but about 10%

are dark gray. This fish species is often prey for large birds that live on the shore. A construction company dumps a load of gravel in the bottom of the lake, resulting in some of it being a dark grey color. What do you predict will happen to this fish population over many years?
Biology
1 answer:
goldfiish [28.3K]3 years ago
8 0
<h2>Proportion of mottled fish </h2>

Explanation:

  • A predator can be defined as an organism that makes the other organisms die to obtain them as food. Prey is the living being which is typically inferior and killed by the predator. Adaptation is a change in the physiology, morphology and genetic makeup of the organism which makes it suitable for survival in an unfavorable environment. Natural selection is the differential survival and reproduction of the organisms which exhibit better traits over the others
  • The population of the mottled fish is likely to increase due to natural selection. As the mottled fish color pattern match with that of the mottled background of the bottom of the lake. This will help the mottled fishes to camouflage the predator wading birds. These mottled fishes will remain undetected from the predator wading birds. The trait of the mottled pattern will be adapted by the light sandy brown fishes and the trait will be passed on the next generation as well. Hence, the proposition of the mottled fish will increase
  • Hence, the right answer is "the proportion of mottled fish will increase over time"

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In garden peas a pure line that is tall with purple flowers is crossed to another pure line that is short with white flowers. Th
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Answer:

See the explanation

Explanation:

Answer 1.

As given that in F1 all are short and white then it can be said according to Mendel's law that short and white are dominant over tall and purple.  

Let S for short s for tall and W for white and w for purple allele.

So the genotype of short purple will be Ssww or SSww. So In first case Ssww self crossed then resultant offsprings will be,

................ Sw .................... sw

Sw ........ SSww ............. Ssww

sw ........ Ssww .............. ssww (tall and purple)

So from this 1/4 will be tall and purple while 3/4 will be short and purple.

In second case SSww only short purple progeny will appear.

Answer 2.

2. a) The female progeny will not show any trait because there are two X chromosome in females , so female offspring can be carrier but not show any trait in case of X- linked trait.

2. b) Half of male offsprings show trait because X is inherited from mother. So the chance of having X-linked recessive allele is 1/2.

2. c) The chance of having X linked affect allele in daughter is 1/2. So the chance of inheriting that X to son will be 1/2 so in total there is chance of 1/4 that son will be affected.

2. d) the chance of first child show this trait will be 1/4 in case of male offspring while 0 in case of female offspring.

Hope this helps!

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3 years ago
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