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2 years ago

SOMEONE HELP ASAP slope of graph

Mathematics

1 answer:

KonstantinChe [14]2 years ago

6 0

Answer:

Step-by-step explanation:

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For which equation would x = 5 be a solution?

tresset_1 [31]

Answer:

The second option.

3x + 6 = 21.

Step-by-step explanation:

3x + 6 = 21.

If x = 5, plug it in.

3 · 5 + 6 = 21

15 + 6 = 21

Hope this helps,

Davinia.

7 0

2 years ago

Write the equation of a line that has a slope of 1/2 and passes through (6, -4). Write your answer in slope-intercept form. PLEA

Tems11 [23]

Answer:

y = 1/2x - 7

Step-by-step explanation:

y = 1/2x + b

-4 = 1/2(6) + b

-4 = 3 + b

-7 = b

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2 years ago

What point is a solution?

vladimir1956 [14]

(3,2) is the solution

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2 years ago

Read 2 more answers

How to solve logarithmic equations as such

Serga [27]

$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

$\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}$

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3 years ago

I need help... on my homework it says to write each expression in radical form, or write each radical and exponential form . For

pantera1 [17]

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2 years ago