So (0, 1) is a point on the line and (1, 4) is a point on the line. To find the equation of the line, you use either
1) y = mx + c
2) y - y1 = m(x - x1)
1) is quicker if you know what c is (the y-intercept), 2) only needs one point on the line to find the equation if you know the gradient
and to find the gradient you divide the difference between two y coordinates by the different between two x coordinates, so the gradient is
m = (y2 - y1) / (x2 - x1)
So let's start:
Using points (0, 1) and (1, 4)
gradient m = (4 - 1) / (1 - 0) = 4
Now for the equation of the line,
1) using y = mx + c
You know that the line intercepts the y-axis at (0, 1), when y = 1, so c = 1.
We worked out the gradient m = 4
So using y = mx + c
y = 4x + 1
2) using y - y1 = m(x - x1)
You use any point on the line, (0, 1) is best because it has easy numbers.
Using the equation y - y1 = m(x - x1) and the point (0, 1) and the gradient m = 4, the equation of the line is
y - 1 = 4(x - 0)
y = 4x + 1
