I think it’s the first option
Assuming the order does not matter, you want the number of combinations of 9 things taken 5 at a time. The combinations can be shown as C(9,5), 9C5.
C(9, 5) =
9/5(9-5) =
9*8*7*6*5 / 5*4
The 5 terms cancel.
9*8*7*6 / 4*3*2 =
9*7*2 =
126
The above change is because 4*2 cancels the 8 in the numerator and 6/3 = 2
Therefore, the solution is 126.
Answer:
The value of the test statistic and degrees of freedom is 2.148 and 11 respectively.
Step-by-step explanation:
Consider the provided information.
The mean annual tuition and fees for a sample of 12 private colleges was 36,800 with a standard deviation of 5,000 .
Thus, n = 12,
σ = 5000
degrees of freedom = n-1 = 12-1 = 11

Formula to find the value of z is: 
Where
is mean of sample, μ is the mean of population, σ is the standard deviation of population and n is number of observations.


Hence, the value of the test statistic and degrees of freedom is 2.148 and 11 respectively.
<span>Postulate 1-2
I believe</span>
W=4 that the answer !!!!!