Answer:
12800
Step-by-step explanation:
Answer:
Step-by-step explanation:
We are given that a and b are rational numbers where
and x is irrational number .
We have to prove a+bx is irrational number by contradiction.
Supposition:let a+bx is a rational number then it can be written in
form
where
where p and q are integers.
Proof:
After dividing p and q by common factor except 1 then we get

r and s are coprime therefore, there is no common factor of r and s except 1.
where r and s are integers.


When we subtract one rational from other rational number then we get again a rational number and we divide one rational by other rational number then we get quotient number which is also rational.
Therefore, the number on the right hand of equal to is rational number but x is a irrational number .A rational number is not equal to an irrational number .Therefore, it is contradict by taking a+bx is a rational number .Hence, a+bx is an irrational number.
Conclusion: a+bx is an irrational number.
Function f(4) = -10 and if g(x) = 2 , x = 0.
To find f(4), we will observe the graph of f(x).
According to the graph of f(x),
when x = 4, y is -10 which means when x is 4 value of f(4) is -10.
To find the value of x when g(x) is 2, we will observe the graph of g(x).
According to the graph of g(x),
when y = 2, x is 0 which means that when x is 0, the value of g(x) is 2.
Hence, f(4) is -10 and x = 0 when g(x) = 2.
To learn more about Function here:
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The perfect squares are 25, 36, 49, 64, 81, 100, 121, 144, 169. You know a number is a perfect square when there is a whole number that can be multiplied by itself to get the number. Example: 25= 5x5
Hope that helps if you need a better explanation let me know.