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Ainat [17]
3 years ago
12

Practical Problem Equation Sort

Mathematics
2 answers:
photoshop1234 [79]3 years ago
6 0

Answer:

Sorry, not sure if i have an answer but ill take the points.

Step-by-step explanation:

i do apologize!

padilas [110]3 years ago
5 0
Same here I need points I don’t do this at all this is my first time I apologize
You might be interested in
PLEASE HELP ASAP
Alja [10]

Answer: x = -1; y = -1

y = 3x + 2

y = -2x - 3

⇔ y = 3x + 2

   3x + 2 = -2x - 3

⇔ y = 3x + 2

    5x = -5

⇔ y = 3x + 2

    x = -1

⇔ y = -1

    x = -1

Step-by-step explanation:

5 0
3 years ago
Exercice 5 (2 points)
yulyashka [42]

Answer:

Hours = 2.5

Minutes = 0.04167

I hope it helps. (j'espère que ça aide)

3 0
3 years ago
Which is the graph of the function f(x) = -√x?
Virty [35]

Answer:

Step-by-step explanation:

The last (fourth) graph is that of the parent function y = √x.  The negative sign in front of √x leads to reflection of this parent function graph in the x-axis.  Thus, the correct graph of f(x) = -√x is the first one.

7 0
4 years ago
Find The Area Of The Rectangle: 2/3 x 5/7
oksian1 [2.3K]

Answer:

10/21 units²

Step-by-step explanation:

2/3 x 5/7 = 10/21 units²

5 0
3 years ago
Read 2 more answers
Can someone explain me this please
AfilCa [17]

\purple{\maltese}\large\underline{\underline{\red{\sf\:\: Given :}}} \\

  • Mass (M) of space shuttle = 1.0 × 105 kg.
  • Altitude (r) = 200.0 km

\\\purple{\maltese}\large\underline{\underline{\red{\sf\:\: To \: \:   Find  :}}} \\

  • The force of gravity that the space shuttle experiences = ?

\\\purple{\maltese}\large\underline{\underline{\red{\sf\:\: Solution :}}} \\ \\

\purple{\maltese}\large\underline{\underline{\sf\:\: using \: formula :}} \\ \\

\bigstar \: \underline{ \boxed{\sf { \pink{g = \frac{G \: M}{{r }^{2} }}}}} \\  \\

\\ ❒\:  \: \underline{\textbf {Putting values \: in \: the \: \: given \: formula :}} \\

\sf \implies \: g = \frac{G \: M}{{r }^{2} }  \\

\sf \implies \: g = \frac{6.67×10^{-11} × 1.0×10^5}{(2×10^5)^{2} }  \\

\sf \implies \: g = \frac{6.67×10^{-6}}{4×10^{10}}\\

\sf \implies \: g = \frac{6.67×10^{-6}}{4×10^{10}} \\

\sf \implies \: g =1.6675×10^{-6-10}\\

\sf \implies \: g =1.6675×10^{-16}\: Newton\\\\

\:\:\:\:\:\:\:\qquad\rule{150pt}{2pt} \\\\

Henceforth, the force of gravity experienced by the shuttle is <u>1.6675×10^N</u>

4 0
2 years ago
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