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STALIN [3.7K]
2 years ago
10

What are the answers for question 1 and 2??

Mathematics
2 answers:
lukranit [14]2 years ago
7 0

Answer:

1) Answer: 3)  ~~x = -3 \pm \sqrt{7}

2) Answer: 3) 2 and -6

Step-by-step explanation:

xeze [42]2 years ago
6 0

Answer:

1) Answer: 3)  ~~x = -3 \pm \sqrt{7}

2) Answer: 3) 2 and -6

Step-by-step explanation:

1)

(x + 3)^2 = 7

x + 3 = \pm \sqrt{7}

x = -3 \pm \sqrt{7}

Answer: 3)~~x = -3 \pm \sqrt{7}

2)

2(x + 2)^2 - 4 = 28

2(x + 2)^2 = 32

(x + 2)^2 = 16

x + 2 = \pm \sqrt{16}

x + 2 = \pm 4

x + 2 = 4   or   x + 2 = -4

x = 2   or   x = -6

Answer: x = 2 or x = -6

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What is 63 over 75 as a decimal?
marissa [1.9K]

Answer:

0.84

Step-by-step explanation:

Use a calculator.  That would be 0.84.

                               3*21

Note that 63/75 = ---------- = 21/25.  Multiplying top and bottom by 4 results

                                3/25                   in 0.84 (so this answer checks out ok)

3 0
3 years ago
Drag each tile to the correct box.
ivolga24 [154]

Answer:

1 and 27, 12 and 33, 6 and 24, 36 and 81, 12 and 96.

Step-by-step explanation:

GCF of 36 and 81: 9

GCF of 1 and 27: 1

GCF of 12 and 33: 3

GCF of 12 and 96: 12

GCF of 6 and 24: 6

3 0
3 years ago
Write an equation parallel to y=-3x-2 through the point (3, -5)
Free_Kalibri [48]

Answer:

y = -3x + 4

Step-by-step explanation:

I graphed the equation and the point given on the graph below. The other line is the equation that is parallel.

If this answer is correct, please make me Brainliest!

3 0
3 years ago
Read 2 more answers
Can someone help me with 11 A and B?
Elan Coil [88]
For 11a its 2:10 because how you would come up with it is by placing pablos free minutes first and then putting pablos paid minutes and 11b is8:25 because once again you would place sams free minutes first and then his paid minutes
6 0
3 years ago
Two complex numbers are given byz1= 3 +j4 andz2= 2 +j3. Determine in both polar andCartesian forms
Marat540 [252]

Answer:

Cartesian

z₁= 3 +4*j

z₂= 2 +3*j

Polar

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

Step-by-step explanation:

for the complex numbers z the cartesian form of is

z= x + y*j

then

1) z₁= 3 +4*j (cartesian form)

2) z₂= 2 +3*j (cartesian form)

the polar form is

z= r* e^jθ

where

r= √(x²+y²) → r₁ = √(3²+4²) = 5 ,  r₂ = √(2²+3²) = √13

and

θ = tan⁻¹ (y/x)  → θ₁  = tan⁻¹ (4/3)= 0.927 rad , θ₂  = tan⁻¹ (3/2)= 0.982 rad

then

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

3 0
3 years ago
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