Question

PLEASE HELP ME WITH THIS PROBLEM

Answer 1

Given:

Length of a rectangle = (3x-3)

Width of the rectangle = (2x+1)

To find:

The area of the rectangle.

Solution:

We know that, area of a rectangle is

$Area=Length \times width$

Putting Length = (3x-3) and width = (2x+1), we get

$Area=(3x-3)\times (2x+1)$

$Area=(3x-3)(2x+1)$

Using distributive property, we get

$Area=3x(2x+1)-3(2x+1)$

$Area=3x(2x)+3x(1)-3(2x)-3(1)$

$Area=6x^2+3x-6x-3$

$Area=6x^2-3x-3$

Therefore, the area of rectangle is $(3x-3)(2x+1)\equiv 6x^2-3x-3$ sq. units.