Answer:
14x+21
Step-by-step explanation:
7*2x=14x
7*3=21
14x+21
hope this helps :9
Given that Relationship B has a lesser rate than Relationship A and that the graph representing Relationship A is a f<span><span>irst-quadrant graph showing a ray from the origin through the points
(2, 3) and (4, 6) where the horizontal axis label is Time in weeks and the vertical axis
label is Plant growth in inches.</span>
The rate of relationship A is given by the slope of the graph as follows:

To obtain which table could represent Relationship B, we check the slopes of the tables and see which has a lesser slope.
For table A.
Time (weeks) 3 6 8 10
Plant growth (in.) 2.25 4.5 6 7.5

For table B.
Time (weeks) 3 6 8 10
Plant growth (in.) 4.8 9.6 12.8 16
</span><span><span>

</span>
For tabe C.
Time (weeks) 3 4 6 9
Plant growth (in.) 5.4 7.2 10.8 16.2
</span><span>
For table D.
Time (weeks) 3 4 6 9
Plant growth (in.) 6.3 8.4 12.6 18.9</span>
<span>

</span>
Therefore, the table that could represent Relationship B is table A.
Well .03 is equal to 3/100 so it is already in simplest form
Take y=3 and plug it into y=-3x+6. This gives you 3=-3x+6. Solve for x, you get x=1. Now plug 1 into y=-3x+6 and you get 3. Answer is (1,3)
Answer:
The perimeter and area of the square are 56 units and 196 square units, respectively.
Step-by-step explanation:
The inner right triangle represents a 45-45-90 right triangle, which has the feature of a hypotenuse whose length is
time the length of any of its legs. If the hypotenuse has a measure of
, then the legs of the triangle have a measure of
.
Now, we are aware that the side length of the square is twice the length of the leg of the right triangle. Then, side length of the square is 14 units long.
Lastly, we know from Geometry that the perimeter and area of the square are represented by the following expressions:
Perimeter
(1)
Area
(2)
Where
is the side length of the square.
If we know that
, then the perimeter and area of the square are, respectively:




The perimeter and area of the square are 56 units and 196 square units, respectively.