![\bf \textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x) = 6.4\implies \log_{10}(x)=6.4\implies 10^{6.4}=x\implies 2511886.43\approx x](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bexponential%20form%20of%20a%20logarithm%7D%20%5C%5C%5C%5C%20%5Clog_a%28b%29%3Dy%20%5Cqquad%20%5Cimplies%20%5Cqquad%20a%5Ey%3D%20b%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Clog%28x%29%20%3D%206.4%5Cimplies%20%5Clog_%7B10%7D%28x%29%3D6.4%5Cimplies%2010%5E%7B6.4%7D%3Dx%5Cimplies%202511886.43%5Capprox%20x)
let's recall that when the base is omitted, "10" is implied.
There is no solution to this
Answer:
%60.66666...
Step-by-step explanation:
<u>Step 1: Make an equation to represent</u>
Percent change of the numbers six and four
6x = 4
<u>Step 2: Divide both sides to get a decimal</u>
6x / 6 = 4 / 6
x = 0.6666....
<u>Step 3: Convert into a percentage</u>
x = 0.6666.... * 100
x = %60.66666...
Answer: %60.66666...
<u>If you meant the other way:</u>
4x = 6
4x / 4 = 6 / 4
x = 1.5
x = 1.5 * 100
x = %150
Answer:
Step-by-step explanation:
the 2nd line can be rewritten as y < x-3
So, any value that is less than both 4x+4 and x-3 will work
Pick any value you want for x, and figure y possibilities
x=0; x-3=-3, 4x+4=4, so y<-3 ... (0,-5) will work
I'm sure you can now come up with other pairs.
If you are asking for how many hours you work, then:
5(3+4)=5*7=35 hours total
