Answer:
<em><u>x=-6, y=-2</u></em>, (As a point) (-6, -2).....The point form is not necessary unless you want to solve the system (of equations) by graphing.
Step-by-step explanation:
By substitution:
x-y=-4 By adding y on both sides,
x=y-4
Now you can substitute x for the expression (y-4)
Plug the (y-4) as x in the other equation.
So -2x+3y=6 becomes
-2(y-4)+3y=6
Now solve:
-2(y-4)+3y=6 distributes out to be
-2y+8+3y=6 Now combining like terms
y+8=6 Subtract 8 on both sides to isolate the variable
<u><em>y=-2</em></u>
Now plug the value -2 in where the y is in any equation (preferably the easier/less complicated one) and solve for x.
So x-y=-4 becomes
x-(-2)=-4
=x+2=-4
=<u><em>x=-6</em></u>
Answer:
The answer is y= -1/3x-5
Step-by-step explanation:
(9, -8) and (-6, -3)
m= y²-y¹/x²-x1
m= (-3)-(-8)/(-6)-9
m= 5/-15
m=-1/3
y=mx+b
y=-1/3x+b
-3=-1/3(-6)+b
-3=2+b
-2 -2
-5=b
The answer is y=-1/3x-5
Answer:
2^5 or 32
Step-by-step explanation:
Answer:
P(2)=0 then x-2 is a factor of P(x)
Step-by-step explanation:
To see if (x-2) is a factor just plug in 2 for x into the polynomial expression.
2(2)^3-3(2)^2-17(2)+30
2(8)-3(4)-34+30
16-12-34+30
4-34+30
-30+30
0
Since P(2)=0 then x-2 is a factor
Answer:
25/-10
Step-by-step explanation:
you plug -5 as b so -5x-5=25
and then plug -15 as a and add 5 so u get -10
