A.) Revenue = price * quantity = px = -1/20x^2 + 1060x
R(x) = -1/20x^2 + 1060x.
b.) Profit = Revenue - Cost = R(x) - C(x) = -1/20x^2 + 1060x - 120x - 5000
P(x) = -1/20x^2 + 940x - 5000
c.) For maximum profit, dP/dx = 0
-1/10x + 940 = 0
1/10x = 940
x = 940 * 10 = 9,400
x = 9,400
Maximum profit = P(9400) = -1/20(9400)^2 + 940(9400) - 5000 = $4,413,000
d.) The price to be charged for maximum profit = -1/20(9400) + 1060 = $590
Answer:
1) a body of air with horizontally uniform temperature, humidity, and pressure.
2) the foremost part or surface of anything. the part or side of anything that faces forward: the front of a jacket.
3) A cold front is often associated with showers and thunderstorms. As it advances, often quite rapidly (50 to 65 km [30 to 40 miles] per hour), the cold air, which is relatively dense, undercuts the displaced warm air, forcing it to rise.
4) Cold Fronts. When a cold front passes through, the weather becomes significantly colder and drier. (It isn't uncommon for air temperatures to drop 10 degrees Fahrenheit or more within an hour of a cold frontal passage.) The weather map symbol for a cold front is a blue curved line with blue triangles.
5) When a cold front passes through, temperatures can drop more than 15 degrees within the first hour. Symbolically, a cold front is represented by a solid line with triangles along the front pointing towards the warmer air and in the direction of movement.
Step-by-step explanation:
Last part ----------------------------------------------------------------------------------------------------------------->
If you divide the first equation by 2 and the second by 3, you get
These equations differ only in their y-intercept, so describe parallel lines. The appropriate choice is ...
... H The lines are parallel.
Answer:
f(x)=3x−1
2
Step-by-step explanation:
The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined. The range is the set of all valid y values. The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.
Interval Notation:
(-∞,∞)
Set-Builder Notation:
{x|x∈R}
The range is the set of all valid
y
values. Use the graph to find the range.
Interval Notation:
(−∞,∞)
Set-Builder Notation:
{y|y∈R}
Determine the domain and range.
Domain:
(−∞,∞),{x|∈R}
Range:
(−∞,∞),{y|y∈R}
These are so great! They are a perfect combination of Physics and pre-calculus! Your max height of that projectile is going to occur at the max value of the parabola, or at its vertex. So we need to find the vertex. The coordinates of the vertex will give us the x value, which is the time in seconds it takes to reach y which is the max height. Do this by completing the square. Begin by setting the equation equal to 0 and then moving the 80 over to the other side. Then factor out the -16. This is all that:
. Take half the linear term which is 4 and square it and add it in to both sides. Half of 4 is 2, 2 squared is 4, so add 4 into the set of parenthesis and to the -80.
. The -64 on the right comes from the fact that when you added 4 into the parenthesis, you had the -16 out in front which is a multiplier. -16 * 4 - -64. So what you really added in was -64. Now the perfect square binomial we created in that process was
. When we move the 144 back over by addition we find that the vertex of the polynomial is (2, 144). And that tells us that it takes 2 seconds for the projectile to reach its max height of 144 feet. To find the time interval in which the object's height decreases occurs from its max height of 144 to where the graph of the parabola goes through the x-axis to the right of the max. To find where the graph goes through the x-axis, or the zeroes of the graph, you factor the polynomial. When you do that using the quadratic formula you get that x = -1 and 5. So at its max height it is at 2 seconds, and by 5 seconds it hits the ground. So the time interval of its height decreasing is from 2 seconds to 5 seconds, or a total of 3 seconds. I think you need the 2 and 5, from the wording of your problem.
