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otez555 [7]
3 years ago
8

Connor and Angie helped take attendance during their schools practice fire drill if the actual count was between 77 and 89 inclu

sive what is the most absolute error could be
Mathematics
1 answer:
wel3 years ago
4 0

Answer:

The most absolute error is 12

Step-by-step explanation:

The formula for absolute error is given by the following relation;

Absolute error, Δx = Value measured, x₀ - Exact (actual) value, x

Δx = x₀ - x

Since the actual count is between 77 and 89, the maximum absolute error will be where the actual value = 77 and the measured value = 89 and vice versa, giving an absolute error of 89 -77 = 12.

The most absolute error = 12.

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Find the sum of the following infinite geometric series, if it exists. 2 + 6 + 18 + 54 +… Does not exist 23,567 25,982 29,034
Sladkaya [172]

Option A: The sum for the infinite geometric series does not exist

Explanation:

The given series is 2+6+18+54+.......

We need to determine the sum for the infinite geometric series.

<u>Common ratio:</u>

The common difference for the given infinite series is given by

r=\frac{6}{2}=3

Thus, the common difference is r=3

<u>Sum of the infinite series:</u>

The sum of the infinite series can be determined using the formula,

S_{\infty}=\frac{a}{1-r}   where 0

Since, the value of r is 3 and the value of r does not lie in the limit 0

Hence, the sum for the given infinite geometric series does not exist.

Therefore, Option A is the correct answer.

8 0
3 years ago
Expand<br> (2x - 3)4 <br><br> Can you help me expand this by using the binomial theorem?
saw5 [17]

The value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4

Evaluate the combination factors.

So, we have:

(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4

Evaluate the exponents and the products

(2x -3)^4 = 16x^4  + 96x^3  +216x^2 -216x + 81

Hence, the value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

Read more about binomial expansions at:

brainly.com/question/13602562

#SPJ1

8 0
1 year ago
What conclusion can be made ?
Zina [86]

Step-by-step explanation:

CD is congruent to EB

CD≈EB

5 0
3 years ago
1.What letter can you draw on a coordinate plane to help you remember the order of the quadrants?
weeeeeb [17]
1. I would call quadrants i, ii, iii, iv as a, b, c, d

<span>2.Which type of variables are usually on the y-axis and represent output?
</span>they usually are the dependent variables, that is, they depend on the x value, such as velocity, price, income.

3.Which type of variables are usually on the x-axis and represent input?
those are the independent variables such as time, distance, price.

<span>4.Which type of slope is represented on a graph as a horizontal line? </span>
the slope of an horizontal line is zero.

<span>5.Find the slope of 2x + 4y = 12
</span>the general form of the line is:
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y = -(1/2)x + 3

hence the slope is -1/2
5 0
3 years ago
What is the unknown fraction 2/10 +__=67/100
sattari [20]
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7 0
2 years ago
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