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Serga [27]
3 years ago
13

Have a great day everyone

Mathematics
2 answers:
kakasveta [241]3 years ago
3 0

Answer:

U too fellow human

Step-by-step explanation:

barxatty [35]3 years ago
3 0

Answer:

Keep things on topic Please, but also Thank You!

Step-by-step explanation: But seriously keep it on topic

You might be interested in
Are 0,2,5 closed or not under addition
kvasek [131]

Answer:

There are closed addition.

Step-by-step explanation:

Closure (mathematics) ... For example, the positive integers are closed under addition, but not under subtraction: is not a positive integer even though both 1 and 2 are positive integers. Another example is the set containing only zero, which is closed under addition, subtraction and multiplication.

So, 0,2,5 are closed addition

Please mark me brainliest.

3 0
4 years ago
I’m really bad at proofs like really bad can someone help with 20 and 21
Nina [5.8K]

Step-by-step explanation:

20.

In each proof, start by looking at what you're trying to prove.  We want to prove that two triangles are congruent.  To do that we use one of the following: SSS, SAS, ASA, or AAS.

To decide which one to use, look at the information given.  We're given two pairs of congruent sides, so we can narrow the strategy down to either SSS or SAS.  We aren't told anything about the third pair of sides, but we <em>can</em> see that ∠JNK and ∠MNL are vertical angles.  We'll use this to show the triangles are congruent by SAS.

1. JN ≅ MN, Given

2. ∠JNK ≅ ∠MNL, Vertical angles

3. NK ≅ NL, Given

4. ΔJNK ≅ ΔMNL, SAS

21.

Repeat the same steps as 20.  Again, we're trying to prove two triangles are congruent, so we have 4 strategies to choose from.  Just like before, we're given two pairs of congruent sides, so we'll use either SSS or SAS.  And again, we aren't told anything about the third pair of sides, but we can see that both triangles are right triangles.  So we'll use SAS again.

1. MN ≅ PQ, Given

2. ∠LMN ≅ ∠NQP, Right angles are congruent

3. LM ≅ NQ, Given

4. ΔNML ≅ ΔPQN, SAS

8 0
4 years ago
Solve for <br><br>10x-6y=-13
marishachu [46]

Answer: x= 3 /5 y+ −13 /10

Step-by-step explanation:

4 0
4 years ago
Make V the subject of the formula E=mv2/2
Dima020 [189]

Answer:

v = ± \sqrt{\frac{2E}{m} }

Step-by-step explanation:

Given

E = \frac{mv^2}{2} ( multiply both sides by 2 to clear the fraction )

2E = mv² ( divide both sides by m )

\frac{2E}{m} = v² ( take the square root of both sides )

v = ± \sqrt{\frac{2E}{m} }

5 0
4 years ago
 A Finance professor created a multiple-choice examination with 100 questions for his students. Each question has five possible
seropon [69]

Answer:

a. 0.011 or 1.1%

b. 31.56% or 0.3156

c. 99.94% or 0.9994

d. 3.42% or 0.0342

Step-by-step explanation:

Given

Number of multiple choice questions = 100

Probability of success for students who have attended lectures and done their homework = 0.85

a. Using binomial distribution

Probability of correctly answering 90 or more questions out of 100

= \sum^{100}_{x=90}\left {100} \atop {x}} \right C (0.85)^x(0.15)^{100-x}\\=0.011

Since,

In Binomial Distribution

P(X=x) =\left {h} \atop {x}} \right.C  P^x q^{n-x}

where x=0,1,...,n

and q=1-P

Probability is therefore 1.1% or 0.011

b. Probability of correctly answering 77 to 83 questions out of 100

= \sum^{83}_{x=77}\left {100} \atop {x}} \right C (0.85)^x(0.15)^{100-x}\\=0.3156

The probability is therefore 31.56% or 0.3156

c. Probability of correctly answering more than 73 questions out of 100

= \sum^{100}_{x=73}\left {100} \atop {73}} \right C (0.85)^x(0.15)^{100-x}\\=0.9994

The probability is therefore 99.94% or 0.9994

d. Assuming that the student has answered randomly

Probability of success = 1/5 = 0.2

Probability of failure = 1 - 0.2 = 0.8

Probability of answering 28 or more questions correctly

= \sum^{100}_{x=28}\left {100} \atop {x}} \right.c  (0.2)^x(0.8)^{100-x}\\=0.0342

The probability is therefore 3.42%

5 0
3 years ago
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