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DiKsa [7]
3 years ago
7

23 greater than b is at least -276

Mathematics
1 answer:
Nuetrik [128]3 years ago
7 0

Answer:

23 + b ≤ -276

Step-by-step explanation:

In this exercise, you're required to write an algebraic expression for the word problem. Thus, you'll write out a mathematical equation using the given values and unknown variable.

Translating the word problem into an algebraic expression, we have;

23 + b ≤ -276

Simplifying further, we have;

b ≤ -276 - 23

b ≤ -299

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9x - 5 =12<br>what is x?​
Ainat [17]

Answer: x = 17/9

Step-by-step explanation: Lets solve for x.

9x - 5 = 12

9x - 5 + 5 = 12 + 5

9x = 17

9x/9 = 17/9

x = 17/9

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Nancy found that x = 1 is one solution to the quadratic equation (x + 2)2 = a. What is the value of a?
solniwko [45]

ANSWER

a=9

EXPLANATION

The given quadratic equation is

{(x + 2)}^{2}  = a

If x=1 is a solution, then it must satisfy this equation:

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3 years ago
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A zoo is keeping track of the weight of a baby elephant.the table shows the weight for the first, second, third, and fourth week
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Hello!

I would say the second option, because it looks like the most reasonable one.  The third and fourth options decrease, but we can see by the chart that in fact, the weight increases. Also, it wouldn't be the first option, because its showing that the wight is always constant and rate doesn't change. However, we can see that this is wrong and the rate actually does change.  Therefore, the second option looks like the most reasonable for this chart.

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83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi
arlik [135]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

Step-by-step explanation:

Information given

\bar X=32.1 represent the sample mean

\mu population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom given by:

df=n-1=8-1=7

The confidence level is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,82)" "=CHISQ.INV(0.95,82)". so for this case the critical values are:

\chi^2_{\alpha/2}=104.139

\chi^2_{1- \alpha/2}=62.132

The confidence interval is given by:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

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3 years ago
Distributive property <br> 12kn+8k
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4k(3n+2) this is basically just factoring out a common multiple which in this case is a k and a 4
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