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tangare [24]
2 years ago
5

A square banner has an area of (4x^2-12x+9) square inches. Write an expression for the perimeter of the banner.

Mathematics
1 answer:
vladimir2022 [97]2 years ago
4 0
The equation can be written as (2x-3)^2
Ans since it is square, then we can take the root of the equation to find on side of the square, which is (2x-3) and by multiplying it by4, we can find the perimeter.
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How are real numbers used to slove problems
Marina86 [1]

Answer:Real numbers are used in measurements of continuously varying quantities such as size and time, in contrast to the natural numbers 1, 2, 3, …, arising from counting. ... The real numbers include the positive and negative integers and fractions (or rational numbers) and also the irrational numbers.

Step-by-step explanation:

3 0
3 years ago
A coat that cost $123 is marked 1/3 off what is the sale price of the coat
alina1380 [7]
I/3 of 123 is 41
41 dollars are taken off, so 123-41=82
the sale price is 82 dollars
4 0
3 years ago
Read 2 more answers
Find two consecutive odd integers whose product is 323
Harrizon [31]
Use a let statement 
first
let x and x + 2 be the number so you write it like this
<u>let x = the first consecutive integer
</u><u>let x + 2 = the second consecutive integer
</u>
second
x(x+2)=323
x^2 + 2x = 323
        -323  -323
x^2 + 2x -323 = 0

third
try to factor -323 so it is 19 and -17
(x + 19) (x - 17) = 0
x = 19 
x = -17

hope this help

4 0
2 years ago
Find the midpoint of CH if C has coordinates (-5,-2) and H has coordinates (9,-4)
Sati [7]

Answer:

(2,1)

Step-by-step explanation:

\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-5,\:-2\right),\:\left(x_2,\:y_2\right)=\left(9,\:4\right)\\\\=\left(\frac{9-5}{2},\:\frac{4-2}{2}\right)\\\\= (\frac{4}{2} , \frac{2}{2} )\\\\=\left(2,\:1\right)

8 0
3 years ago
Read 2 more answers
Given points A (-5, 6) and B (7, -1), find: Distance, Midpoint, and Slope
a_sh-v [17]
We have that
<span>points A (-5, 6) and B (7, -1)

Part A)
find the distance
d=</span>√[(y2-y1)²+(x2-x1)²]-------> d=√[(-1-6)²+(7+5)²]----> d=√(49+144)
d=√193  units

Part B)
find the midpoint
ABx=(x1+x2)/2-----> (-5+7)/2-----> ABx=1
ABy=(y1+y2)/2-----> (-1+6)/2-----> ABy=2.5

the midpoint is (1,2.5)

Part C)
find the slope
m=(y2-y1)/(x2-x1)-----> m=(-1-6)/(7+5)--------> m=-7/12

the slope m=-7/12
4 0
3 years ago
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