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3 years ago

How much do you need to subtract from 83/10 to make 8

2 answers:

7 0

83/10 as a fraction would mean you had to divide 83➗10 which equals 8.3 so you would need to subtract .3 from 8.3 to get 8

Paul [167]3 years ago

4 0

Answer:

Subtract 80 from 83 . The result of division of 8310 is 8 with a remainder of 3 .

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What are the vertical and horizontal asymptote of f(x)=2x/x-1

makvit [3.9K]

F(x)=2x/(x-1)

Denominator cannot be equal 0.
x-1=0
x=1 is vertical asymptote.

To find horizontal asymptote
we need divide the coefficients before x
y=2x/x=2,because when x becomes really big (x---->∞) , value of 1 will not influence the result .
y=2 is horizontal asymptote

6 0

3 years ago

A store pay $120 for a bicycle. The store has a 60% markup policy. What is the selling price of the bicycle?

Zielflug [23.3K]

The selling price will be $192

$120 x 60% = $72 markup

$120 + $72 = $192

7 0

2 years ago

Read 2 more answers

Can someone please solve this using quadratic formula <br><br> 2x^2 -7x -15=0

saw5 [17]

Step-by-step explanation:

a=2

b=-7

c=-15

-(-7)+-sq root (-7)²-4(2)(-15) / 2(2)

7 +- sq root 169 / 4

7+- 13 / 4

7+13 / 4, 7-13 / 4

x=5 x=-3/2

7 0

2 years ago

A line segment has (x1, y1) as one endpoint and (xm, ym) as its midpoint. Find the other endpoint (x2, y2) of the line segment i

Levart [38]

Answer: (a) ( $x_{2},y_{2}$ ) = (3,2)

(b) ( $x_{2},y_{2}$ ) = (19,-7)

Step-by-step explanation: Midpoint of a segment is halfway between 2 endpoints. It is calculated using the formulas:

$x_{m}=\frac{x_{1}+x_{2}}{2}$

$y_{m}=\frac{y_{1}+y_{2}}{2}$

Isolating $x_{2}$ :

$2x_{m}=x_{1}+x_{2}$

$x_{2}=2x_{m}-x_{1}$

And $y_{2}$ :

$2y_{m}=y_{1}+y_{2}$

$y_{2}=2y_{m}-y_{1}$

(a) Replacing values and calculating $x_{2}$ :

$x_{2}=(2*2)-1$

$x_{2}=3$

Calculating $y_{2}$ :

$y_{2}=[2*(-1)]-(-4)$

$y_{2}=2$

$(x_{2},y_{2})=(3,2)$

(b) $x_{2}=(2*5)-(-9)$

$x_{2}=19$

$y_{2}=(2*6)-19$

$y_{2}$ = -7

$(x_{2},y_{2})=(19,-7)$

8 0

3 years ago

Read 2 more answers

Jason tossed a fair coin 3 times. What is the probability of getting a head and two tails in any order 1.3/8 2.4/8 3.5/8 4.6/8 p

ladessa [460]

Answer:

1. 3/8

Step-by-step explanation:

Total tossed times = 3

Total Possibilities = 8

Possibilities = (Head, Head, Head), (Tails,Tail,Tails), (Head,Head,Tails), (Head,Tail,Head), (Tails,Head,Head), (Head,Tail,Tail), (Tail,Tail,Head), (Tail,Head,Tail)

Number of options with a head and two tails = 3

So, Probability = Number of correct options ÷ Number of total possibilities

= 3 ÷ 8 or 3/8

4 0

3 years ago