Ask question

Ask question

All categories

3 years ago

6

If g(x) = 3x - 1 and if g(a) = 7, then which of the following is the value of a?

2 answers:

ludmilkaskok [199]3 years ago

7 0

Answer:

8/3

Step-by-step explanation:

So if a=x then 3a-1=7 therefore 3a=8 and a=8/3

Vaselesa [24]3 years ago

5 0

Answer:

So,

$g(x) = 3x - 1$

And,

$g(a) = 3a - 1$

But, given g(a) = 7

So, from 2nd and 3rd step,

3a-1=7

3a=6

Therefore, a = 2

You might be interested in

The index number representing the price level changes from 109 to 113 in one year. The inflation rate during the year is _____ p

Dima020 [189]

First, get the difference between the price level changes.

$113-109=4$

Then, divide it by the initial price level, which is 109.

$\frac{4}{109}=0.0367$

Multiply by 100 to get its percent.

$0.0367\times100=3.67$

Thefore, the inflation rate during the year is 3.67 percent.

8 0

1 year ago

Helppppppppppppppppp

Elodia [21]

Answer:

hrs =4

Step-by-step explanation:

550-11

200-x

cross multiply

550x=200×11

550÷550=2200÷560

x=4

3 0

3 years ago

Is this correct? and how do u solve it?

Leona [35]

I’m not sure if your answer is right but here’s how to solve it

4 0

3 years ago

Read 2 more answers

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

Ayudaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Nady [450]

Answer:

Okay, hello to you too.

5 0

3 years ago

Read 2 more answers