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sergiy2304 [10]
3 years ago
8

Would really appreciate the help!:(

Mathematics
1 answer:
horrorfan [7]3 years ago
5 0

Answer:

b is 285

Step-by-step explanation:

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If there are 3 hearts and 2 stars what is the value of ONE star?
Nikolay [14]
1.5

Explanation: 3 is total. You have two stars. 1.5+1.5=3
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What is the y-intercept? ​
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(0,7)

Step-by-step explanation:

The y-intercept of a graph is the point where the graph crosses the y-axis.

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3 years ago
1. A football team loses 3 yards and then gains 3 yards.
Ganezh [65]

6 yards first they minused 3 then they added 3 so the overall is 6 3+3=6

pls give brainliest

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3 years ago
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In a local ice sculpture contest, one group sculpted a block into a rectangular based pyramid. The dimensions of the base were 3
masha68 [24]

Answer:

1. The amount of ice needed for the sculpture is 18 m³

2. The amount of fabric needed to manufacture the umbrella is 0.757 m²

3. The height of the cone is 37.5 cm

4. The largest possible storage area which is obtained by attaching the storage area to the back of the building is 87.11 m²

Step-by-step explanation:

1. The volume, V, of a rectangular pyramid = \dfrac{1}{3} \cdot B \cdot h

Where:

B = Base area = Length, L  × Width, W

h = Height of the pyramid = 3.6 m

L = 5 m

W = 3 m

The volume = 1/3 × 5 × 3 × 3.6 = 18 m³

The amount of ice needed for the sculpture is 18 m³

2) The surface area of a cone = π·r·s

s = Slant height

r = Radius of the cone's base = 0.4 m

h = The height of the cone = 0.45m

s = √(0.4² + 0.45²) = (√145)/20

The surface area of the cone = π × 0.4 × (√145)/20 = 0.757 m²

The amount of fabric needed to manufacture the umbrella is 0.757 m²

3) The volume, V of the cone = 150 cm³

The base area, A_b, of the cone = 12 cm²

The height of the cone = h

We note that the volume of a cone = \dfrac{1}{3} \cdot A_b \cdot h

Therefore;

\dfrac{1}{3} \times 12 \times  h = 150

4·h = 150

h = 150/4 = 37.5 cm

The height of the cone = 37.5 cm

4) The storage area at the back corner  with four sides = 100 m²

The storage area at the back of the building with three sides = 98 m²

Given that the available riling = 28 m, we have;

For maximum area the four sides should be equal, hence dimension of each side = 28/4 = 7

The area of storage space that can be fenced on four sides at the back corner = 7 × 7 = 49 m²

At the back of the building only three sides need fencing, we therefore have;

The side length = 28/3 = 9\frac{1}{3}

The area fenced = \left 9\frac{1}{3} \right  \times 9\frac{1}{3}  = 87\frac{1}{9} \ m^2 = 87.11 m²

Therefore, the largest possible storage area, 87.11 m², is obtained by attaching the storage area to the back of the building.

5 0
4 years ago
Find the sum of the even integers between 30 and 70
Marat540 [252]

we have to find sum of even integer between 30 and 70

first term is 32

a_1=32

a_2=34

......

a_n=68

common difference is

d=2

firstly , we will find n

we can use formula

a_n=a_1+(n-1)d

68=32+(n-1)*2

n=19

now, we can find sum

sum=\frac{19}{2} (32+68)

sum=950.............Answer

6 0
4 years ago
Read 2 more answers
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