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o-na [289]
3 years ago
15

Original: $75 new: $60

Mathematics
2 answers:
irina1246 [14]3 years ago
5 0

Answer:

Not sure what your question is asking, if you give me more information I can help you.

nadezda [96]3 years ago
4 0

What's the question?

If it's "What's the difference?" or something like that, then the answer is 15. :)

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6 2/3 divided by 5/6
Yuki888 [10]
[6+2/3] : [5/6]
[20/3]:[5/6]
[20/3]x[6/5]
[120/15]
=8


--------------
3 0
3 years ago
Answer 2. 3. And 4.
WARRIOR [948]

Answer:

For question 2 :

1 <

2>

3=

Step-by-step explanation:

Basically those triangle arrow things are called 'greater than signs'

So , you need to say which number is bigger than the other or if they are equal. For example :

3>1

1<7

1=1

8 0
3 years ago
Read 2 more answers
Is 2/9 a perfect square
Vesna [10]
Ummm yes i think so. correct me if wrong
6 0
3 years ago
An elevator has a placard stating that the maximum capacity is 1580 lb-10 passengers.​ So, 10 adult male passengers can have a m
disa [49]

Answer:

a) 0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb

b) No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 160 lb and a standard deviation of ​35 lb.

This means that \mu = 160, \sigma = 35

Sample of 10:

This means that n = 10, s = \frac{35}{\sqrt{10}} = 11.07

a) Find the probability that it is overloaded because they have a mean weight greater than 158 lb.​

This is 1 subtracted by the pvalue of Z when X = 158. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{158 - 160}{11.07}

Z = -0.18

Z = -0.18 has a pvalue of 0.4286

1 - 0.4286 = 0.5714

0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb.

b.) Does this elevator appear to be​ safe?

No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

8 0
3 years ago
Number 4 and 5. The topic is sample spaces. I just don’t understand and know how to solve. If u can help please do!!
Colt1911 [192]

Ok so the P means probability and on the first one c is 1 of 3 of the total number of of letters in the spinner, and so is g

What that means is that they both have 1/3 probable chance of getting picked or 33.3% but it is most likely asking for a fraction so use 1/3

For 5 it’s more difficult

What you have to do is find the probability of heads and tails

Which is 1/2

D is 1/3

And the vowels are A and E which is 2/3

So you would multiply all the fractions and your answer would be ( work; 1/2 x 1/3 x2/3=) 1/18

5 0
3 years ago
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