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labwork [276]
2 years ago
9

Randy rented a rectangular storage shed with the volume of 357 ft does it sheds height is 8 and 1/2 ft and the width of is 6 ft

what is the length of the shed
Mathematics
1 answer:
ollegr [7]2 years ago
7 0

Answer:

7 feets

Step-by-step explanation:

Volume of shed, V = 357 feet³

Height of shed, H= 8 1/2 fts

Width of shed, W = 6 ft

Using the relation :

Volume = Length * width * height

357 = L * 6 ft * 17/2 feets

357 feets³ = L * 51 feets²

L = 357 feets³ / 51 feets²

Length, L = 7 feets

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The front of a tent is an equilateral triangle with the ratio of its base, b, to its height, h, given by b/h=2/√ 3 . Which equat
Agata [3.3K]
Picturing the tent helps, but we can actually solve this question using simple algebra and no knowledge of triangles. 
The key is this function:
(b/h) = 2/√3  
We want to get h by itself. First, multiply both sides by h:
b = h(2/√3)       Now multiply both sides by the reciprical, (√3/2)
(√3/2) b = h

Therefore, the answer is C) h= b(√3/2)
3 0
3 years ago
If 400 dpi equals 3.6 and 800 equals 1.8. What does 1000 dpi equal to?
laiz [17]

Answer: The numbers are showing in descending order 3.6-1.8= 1.8 = 1.8 is half of 3.6 - therefore if 1200 is half again = 0.8 then what lies between 1.8 and 0.8?  Answer to 1000 is 0.8 +5 = 1.3

Step-by-step explanation:

5 0
3 years ago
Please help with this. I only need help with the first question I have the second one figured out,
lutik1710 [3]

Answer:

m∠WZX = 41°

Step-by-step explanation:

diagonals bisect angles and opposite angles are congruent

therefore, ∠WXY ≅ ∠WZY

∠WZY must equal [360 - 2(68)] ÷ 2 which equals 112°

If ∠WXZ = 71° then so does ∠XZY

Which means that ∠WZX must equal 112-71 which is 41°

6 0
3 years ago
Read 2 more answers
The set of natural numbers x that satisfy x + 8 = 5
Maksim231197 [3]

Answer:

The set of natural numbers can be denoted as: {} (null set) because no natural number will satisfy the given equation.

Step-by-step explanation:

Given equation:

x+8=5

To find the set of natural numbers that satisfies the above equation.

Solution:

In order to find the set of solutions for the equation, we will solve it for x

We have:

x+8=5

Subtracting both sides by 8.

x+8-8=5-8

∴ x=-3

Thus, we get only one solution for x that satisfies the given equation but it is not a natural number. -3 is an integer.

Set of natural numbers {1,2,3,4,5,6........}

Thus, we can say the set of natural numbers that satisfies the equation is a null set {}.

8 0
3 years ago
Solve the initial value problem where y′′+4y′−21 y=0, y(1)=1, y′(1)=0 . Use t as the independent variable.
igor_vitrenko [27]

Answer:

y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7

So, the solution of the equation is

y = Ae^{m_{1} t} + Be^{m_{2} t}

where m₁ = 3 and m₂ = -7.

So,

y = Ae^{3t} + Be^{-7t}

Also,

y' = 3Ae^{3t} - 7e^{-7t}

Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

y(1) = Ae^{3X1} + Be^{-7X1}\\1 = Ae^{3} + Be^{-7}\\Ae^{3} + Be^{-7} = 1      (1)

y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}

Substituting A into (1) above, we have

\frac{7}{3}B e^{-10}e^{3} + Be^{-7} = 1      \\\frac{7}{3}B e^{-7} + Be^{-7} = 1\\\frac{10}{3}B e^{-7} = 1\\B = \frac{3}{10} e^{7}

Substituting B into A, we have

A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}

Substituting A and B into y, we have

y = Ae^{3t} + Be^{-7t}\\y = \frac{7}{10} e^{-3}e^{3t} + \frac{3}{10} e^{7}e^{-7t}\\y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

So the solution to the differential equation is

y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

6 0
3 years ago
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