1 < x < 5
Left side is 1 and right is 5
There is no information given about point V, so any answer will do for the question asked.
If we assume the intent is to ask about the image of point Z, then its coordinates will be 0.8 times those of point Z.
Z' = 0.8×(5, -4)
Z' = (0.8×5, 0.8×(-4)) = (4, -3.2)
The appropriate choice seems to be
C (4, -3.2)
So to solve problems like these you can work out each equation by substituting the x and y with the coords from the vertex (2,-4) and which ever one is true is the corresponding equation.
Lets try the first one
A) y = 2( x-2)^2-4 this would become
-4 = 2(2-2)^2-4 we solve this and get
-4 = 2(0)-4
-4 = -4
so it seems like A is the correct answer, of course we'd wanna check out the other answers just to be sure.
Lets try one and do C
C) -2 = 2(-4-2)^2+2
-2 = 2(-8)^2+2
-2 = 130
These aren't equal so this can't be our equation
So you can also do one more just to be super sure you have the right answer but I think A is the correct one :)
The distance is (-4, 4)
Explanation: I moved down 4 cubes (negative) and moved right 4 cubes (positive).
I hope I am right :)
