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iogann1982 [59]
2 years ago
13

Mr. Green paid $7.50 for a set of dry erase markers. He used a $2.00 coupon for his purchase. Write AND solve an equation that r

epresents the difference between d, the original price of the markers and the coupon. Solve for d.
Mathematics
1 answer:
dalvyx [7]2 years ago
6 0

Answer:

d - 2 = 7.50

$9.50

Step-by-step explanation:

Given that:

Money paid by Mr. Green for a set of dry erase markers = $7.50

Coupon used for the purchase = $2.00

To find:

The equation and solution to represent the difference the original price d of the markers and the coupon.

Solution:

Given that, the original price of the dry erase markers = $d

Coupon amount = $2.00

Amount paid = $7.50

The equation can be made by subtracting the coupon amount from the original price and comparing it with the amount paid by Mr. Green for the purchase.

Original price = $(d - 2)

d - 2 = 7.50

Solving the above equation by adding 2 on both the sides:

d -2+2= 7.50+2\\\Rightarrow d = \$9.50

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Step-by-step explanation:

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2 years ago
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What is 2 1/2 divided by 1/3 {pls hurry the teacher is not letting us use brainly}
katovenus [111]

Answer:

7 1/2

Step-by-step explanation:

2 1/2 ÷ 1/3

Change to an improper fraction

(2*1+2)/2 ÷ 1/3

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8 0
2 years ago
An education center offers a total of 400 math, physics and
Vikentia [17]

Answer: 30

Step-by-step explanation:

3+4+3=10 400/10=40 so each has 40 so math has 120 120*25=3000 for physics is 4*40 so 160 160*20=3200 9800-3000-3200=3600 3*40=120 3600/120=30

8 0
3 years ago
Tania bought 4 more pounds of pears than Wilma. Together, Tania and Wilma bought 18 pounds of pears.
horrorfan [7]
The equation would be (x+4)+x=18. X stands for the amount of pears Wilma bought, and (x+4) is the amount of pears Tania bought (because she bought four more pounds than Wilma). (X+4)+x=18 2x+4=18 (now you subtract four from both sides) 2x=14 (to get x by itself, divide both sides by 2) X=7 Wilma bought 7 pounds of pears :3
7 0
3 years ago
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A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg
polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

P(X = x) = nCx p^{x} q^{n - x}

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662

Finally, the probability that 2 or fewer students will withdraw is

P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355

b) Compute the probability that exactly 4 will withdraw.

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0
3 years ago
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