There are 4 teams in total and each team has 7 members. One of the team will be the host team.
Tournament committee will be made from 3 members from the host team and 2 members from each of the three remaining teams. Selecting the members for tournament committee is a combinations problem. We have to select 3 members out 7 for host team and 2 members out of 7 from each of the remaining 3 teams.
So total number of possible 9 member tournament committees will be equal to:

This is the case when a host team is fixed. Since any team can be the host team, there are 4 possible ways to select a host team. So the total number of possible 9 member tournament committee will be:

Therefore, there are 2917215 possible 9 member tournament committees
Answer:
48in sq
Step-by-step explanation:
8*12/2=8*6=48
Answer:
1/3 =0.33
Step-by-step explanation:
<em>ju</em><em>st</em><em> </em><em>subst</em><em>itute</em><em> </em><em>the</em><em> </em><em>va</em><em>lues</em><em> </em><em>of</em><em> </em><em>x</em><em> </em><em>and </em><em>y</em><em> </em><em>int</em><em>o</em><em> </em><em>th</em><em>e</em><em> </em><em>exp</em><em>ression</em><em> </em><em>to</em><em> </em><em>get</em>
<em>4</em><em>(</em><em>2</em><em>)</em><em>+</em><em>1</em><em> </em><em>/</em><em>3</em><em>(</em><em>3</em><em>)</em><em>^</em><em>2</em>
<em>=</em><em>8</em><em>+</em><em>1</em><em> </em><em>/</em><em>3</em><em>×</em><em>9</em>
<em>=</em><em>9</em><em>/</em><em>2</em><em>7</em>
<em>=</em><em>1</em><em>/</em><em>3</em>
<em>=</em>0.33
It would be 3 with be on the side and then 2/10