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kramer
2 years ago
14

-(-8+5)+{-4+[-7+(-9-5)+3]}

Mathematics
1 answer:
Inessa05 [86]2 years ago
3 0
-(-8+5)+(-4+(-7+(-9-5)+3))
-(-8+5)+(-4+(-7+(-14)+3))
-(-8+5)+(-4+(-7-14+3))
-(-8+5)+(-4+(-18))
-(-8+5)+(-4-18)
-(-3)+(-22)
3+(-22)
3-22
19
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Maria’s suitcase has a mass of 14 kilograms. Her sister’s suitcase
nadya68 [22]

Answer:

Maria

Step-by-step explanation:

Marias suitcase is heavier as 1600 grams to kg is 1.6kg which is less than Marias suitcase which weighs 14kg hope this helps:)

7 0
2 years ago
Please help me with this question I will give brainliest.
Ainat [17]

Answer:

All you need to remember is the rules

Step-by-step explanation:

Let us remember

a to the m power x a to the nth power is = a to the m+n power. (add the exponents)

And

a to the m power ÷ a to the nth power is = a to the m-n power. (subtract the exponents) So

14 to the -4 power x 14 to the 7 power= 14 to the -4+7 which is equal to 14 to the 3rd power

6 0
3 years ago
A tank contains 10 liters of pure water. Saline solution with a variable concentration 5 grams of salt per liter is pumped into
algol [13]

Answer:

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

Step-by-step explanation:

The mass flow rate dQ(t)/dt = mass flowing in - mass flowing out

Since 5 g/L of salt is pumped in at a rate of 4 L/min, the mass flow in is thus 5 g/L × 4 L/min = 20 g/min.

Let Q(t) be the mass present at any time, t. The concentration at any time ,t is thus Q(t)/volume = Q(t)/10. Since water drains at a rate of 4 L/min, the mass flow out is thus, Q(t)/10 g/L × 4 L/min = 2Q(t)/5 g/min.

So, dQ(t)/dt = mass flowing in - mass flowing out

dQ(t)/dt = 20 g/min - 2Q(t)/5 g/min

Since the salt just begins to be pumped in, the initial mass of salt in the tank is zero. So Q(0) = 0

So, the initial value problem is thus

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

3 0
2 years ago
A jar contains 8 4/9 pounds of jam. If Sam eats 3 2/5 pounds of the jam, how many pounds of jam remains in the jar?
zepelin [54]
\bf 8\frac{4}{9}\implies \cfrac{8\cdot 9+4}{9}\implies \cfrac{76}{9}
\\\\\\
3\frac{2}{5}\implies \cfrac{3\cdot 5+2}{5}\implies \cfrac{17}{5}\\\\
-------------------------------\\\\
\cfrac{76}{9}-\cfrac{17}{5}\impliedby \textit{let's use an LCD of 45}\implies \cfrac{5\cdot 76-9\cdot 17}{45}
\\\\\\
\cfrac{380-153}{45}\implies \cfrac{227}{45}\implies \boxed{5\frac{2}{45}}
\\\\\\
5\frac{2}{45}\implies \cfrac{5\cdot 45+2}{45}\implies \cfrac{227}{45}
5 0
3 years ago
NEED THE ANSWER ASAP PLEASE
timurjin [86]

Answer:

2

Step-by-step explanation:

\frac{y1 - y2}{x1 - x2}  \\  \frac{2 - 6}{ - 5 - ( - 3)}  \\  \frac{ - 4}{ - 5 + 3}  \\  \frac{ - 4}{ - 2}  \\  = 2

8 0
3 years ago
Read 2 more answers
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