128 = a + + 4(a + 10) + (a + 10)
128 = a + 4a + 40 + a + 10
128 = 6a + 50
128-50 = 6a
78 = 6a
13 = a
1st = a = 13
2nd = 4(a + 10) = 4(23) = 92
3rd = a + 10 = 23
Since sum indicates addition, you want to add the two terms together.
B + (5x2)
If the answer needs to be simplified, you can do the multiplication to get:
B + 10
Answer: b , d , e ( hope this helps ) :D
Answer:
Graph is in the picture below
Step-by-step explanation:
