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3 years ago

A)Jodis car used 12 gallons of gas to travel 456 miles. how many miles did her car travel per gallon of gas? show your work.

Mathematics

1 answer:

Tresset [83]3 years ago

7 0

a) Jodi's car traveled 38 miles per gallon of gas. We know this because by dividng the amount of miles traveled by number of gallons Jodi has in her car we can find how many miles she travels per gallon of gas.

So our equation would be 456 / 12 = 38

b) The cost per gallon of gas was $3.74. We can find this answer by dividing how much she paid ($44.88) by how many gallons she bought (12).

So our equation would be 44.88 / 12 = 3.74

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What is the net force on a 1,000 kg object accelerating at 3 m/s2 ?

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3 $3 \leq m+1.4$

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Solve the problem give the equation using x as the variable and give the answer. If 1 is subtracted from a number and this diffe

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Answer:

x=6

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3 years ago

What is the decimal for 4 2/3?

muminat

4.67 would be a rounded answer. Really it's 4.666666666666666666 (the 6 go on forever) but we can't write that out.

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3 years ago

*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

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3 years ago

What’s the correct answer

laila [671]

C. 502

All you need to do is multiply the number if sales by the percentage in decimal form. Using DPR I know that 11% is equal to 0.11, so 4,560(0.11) is 501.60. That can be rounded to 502 sales that were shirts.

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3 years ago