The perpendicular line will have an equation of y=3/4x-3/4
To find this, we first have to solve our equation for slope intercept form.
8x + 6y = -5 ----> subtract 8x
6y = -8x + -5 ----> divide by 6
y = -4/3x - 5/6.
So we know the slope of this equation to be -4/3. Since perpendicular lines have opposite and reciprocal slopes, we know we can simply flip the fraction and make it a negative to get the new slope of 3/4. Since B is the only option with that slope, we know it to be the correct answer.
Answer:
The balance after the payment is $1263.84.
Step-by-step explanation:
The formula for amount after compound interest is

Where, P is principal, r is rate of interest, n is number of time interest compounded in a period, number of periods.
According to the given information,
P=1455.69
r=0.128
n=365
t=45
Put these values in the above formula,


The amount after compound interest is $1478.84. Add late fee chages $35 in this amount and subtract the payment of $250. So, the balance amount after payment is

Therefore the balance after the payment is $1263.84.
Answer:
1. A=300miles B=300
2.A=50mph B=40mph
3.A=300miles B=200miles
Step-by-step explanation:
<em><u>1.</u></em>
Simply just read the graph
<em><u>2.</u></em>
do not let line B fool you, car b may look like it was faster, but unlike car a it started at 100 miles rather than 0 miles
<em><u>3.</u></em>
Just like 2, do not be fooled, you have to subtract to find b but a is easily found
I hope this helps u pls give a brainliest and a thx ;)
Step-by-step explanation: look so if you have
shcool A its 8v+4b=12
and
School B: 12v+4b= 16
since both classes used 4 busses we can use elimination by subtracting the A class Equation from the b class equation to solve from v for its value Then, use either equation and the now found value for v to solve for b.
You should find part of the process to be
12v+4b-(8v+4b)=12-16 which shows the van holds only a few people even before continuing the solution.
Answer -4
Answer:
A perfect square is a whole number that is the square of another whole number.
n*n = N
where n and N are whole numbers.
Now, "a perfect square ends with the same two digits".
This can be really trivial.
For example, if we take the number 10, and we square it, we will have:
10*10 = 100
The last two digits of 100 are zeros, so it ends with the same two digits.
Now, if now we take:
100*100 = 10,000
10,000 is also a perfect square, and the two last digits are zeros again.
So we can see a pattern here, we can go forever with this:
1,000^2 = 1,000,000
10,000^2 = 100,000,000
etc...
So we can find infinite perfect squares that end with the same two digits.