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2 years ago

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What is the perimeter of polygon LMNPQ

2 answers:

frez [133]2 years ago

7 0

Answer:

The total distance of the outer sides of a closed figure is known as the perimeter. It is the total length of all sides of a polygon. Perimeter = Sum of all sides.

Formula:

The sum of interior angles of a polygon with “n” sides =180°(n-2) Number of diagonals of a “n-sided” polygon = [n(n-3)]/2. The measure of interior angles of a regular n-sided polygon = [(n-2)180°]/n. The measure of exterior angles of a regular n-sided polygon = 360°/n.

hope it helps

mario62 [17]2 years ago

3 0

Answer: c for maps

Step-by-step explanation:

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Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti

hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$

but we will find sample size "n"

$\sqrt{n} = \frac{z_{a} S.D}{maximum error}$

Squaring on both sides , we get

$n = (\frac{z_{a} S.D}{maximum error})^2$

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

$n = (\frac{z_{a} p(1-p)}{maximum error})^2$

n≤ $(\frac{2.56X\frac{1}{2} }{0.02}) ^{2}$ ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is n = 4225

<u>verification</u>:-

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$ = $\frac{2.56 1/2}{\ \sqrt{4225} }$ = 0.0196

substitute all values and simplify we get maximum error is 0.02

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2 years ago

Tran had 40.00 saved for a new bike. Four weeks later he had saved $68.00. At what rate of change did Tran’s savings grow?

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3 years ago

The diameter of a iron sphere is 8 cm. It is beaten and drawn into a wire with a diameter of 2 mm. Find the length of the wire.

djyliett [7]

Answer : The length of the wire is, 8533 cm

Step-by-step explanation :

As the iron sphere is beaten and drawn into a wire. That means, their volume will be equal.

Volume of iron sphere = Volume of cylindrical wire

The formula will be:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

where,

$r_1$ = radius of sphere = $\frac{Diamtere}{2}=\frac{8cm}{2}=4cm$

$r_2$ = radius of cylindrical wire = $\frac{Diamtere}{2}=\frac{2mm}{2}=1mm=0.1cm$

h = height of cylindrical wire or length of wire

Now put all the given values in the above formula, we get:

$\frac{4}{3}\pi r_1^3=\pi r_2^2h$

$\frac{4}{3}\times r_1^3=r_2^2h$

$\frac{4}{3}\times (4)^3=(0.1)^2h$

$h=8533.33cm\approx 8533cm$

Therefore, the length of the wire is, 8533 cm

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3 years ago

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Tom [10]

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Step-by-step explanation:

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