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3 years ago

10 points please help

Mathematics

1 answer:

jolli1 [7]3 years ago

4 0

6* 8.4
7* 3.5
8* -6
9* 10.899
10* 11.1
11* 2.4
12* 0.06
13* 2.2
14* 15.2
15* 11.7
16* -3.4

explanation: Sorry i couldn’t finish and i hope these are correct! I’m not that good at math but good luck

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There are 120 blocks left.

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Find the measure of the arc

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The answer is kindly 21 (100% correct)

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2 years ago

Marcia has $84 less than three times as much as sue. together they have $132. how much money does marcia have?

Brut [27]

Let x = sue
and then let 3x-84 = marcia
therefore
(x)+(3x-84)=132
4x-84=132
4x=216
x=54

however just solving for x doesnt completely solve. it only shows sues money because x = sue
for marcia
3x-84
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therefore Marcia has 78$.

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3 years ago

Find the volume of the prism.<br> 9km 8km 6km

HACTEHA [7]

The correct answer is option B which is the volume of the prism is 216 km³.

<h3>What is the volume of the prism?</h3>

A prism is a three-dimensional solid with a triangular base called a triangular prism. The volume of the triangular prism is equal to the product of the area of the base and the height of the prism.

The volume of the prism will be calculated by using the formula below:-

V = Area of the base x Height

Since the base is a right-angle triangle so we will calculate the area of the right-angle triangle.

V = Area of the triangle x Height

V = ( 1/2 ) x 8 x 6 x ( 9 )

V = 216 km²

Therefore the correct answer is option B which is the volume of the prism is 216 km³.

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brainly.com/question/1972490

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2 years ago

The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand

Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 18.6, \sigma = 5.9$

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21 - 18.6}{5.4}$

$Z = 0.44$

$Z = 0.44$ has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have $n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768$