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PSYCHO15rus [73]
3 years ago
8

10 points please help

Mathematics
1 answer:
jolli1 [7]3 years ago
4 0
6* 8.4
7* 3.5
8* -6
9* 10.899
10* 11.1
11* 2.4
12* 0.06
13* 2.2
14* 15.2
15* 11.7
16* -3.4

explanation: Sorry i couldn’t finish and i hope these are correct! I’m not that good at math but good luck
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(8x – 20)-16 =10x+51
Lemur [1.5K]

When solving this equation, you get the answer as -43.5.

To solve, we simply need to collect like-terms and then rearrange to get x on one side and numbers on the other:

(8x - 20) - 16 = 10x + 51

8x - 36 = 10x + 51

- 8x

-36 = 2x + 51

- 51

-87 = 2x

÷ 2

-43.5 = x

I hope this helps!

6 0
3 years ago
The article "High Cumulative Risk of Lung Cancer Death among Smokers and Nonsmokers" (P. Brennan, et al. American Journal of Epi
Dmitry [639]

Answer:

a)False: In a sample of 100 men who are heavy smokers, exactly 24 of them will contract lung cancer.

b)True: In a sample of 100 men who are heavy smokers, the number who will contract lung cancer is likely to be close to 24.

c)True: As more and more heavy-smoking men are sampled, the proportion who contract lung cancer will approach 0.24. Circle one: TRUE FALSE

7 0
3 years ago
Use Euler's formula to write 3+3i^3 in exponential form.
Alex_Xolod [135]

21−=2(2−)=2cos(−1)+2 sin(−1)

−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2

Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.

complex-numbers

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edited Mar 6 '17 at 4:38

Richard Ambler

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asked Mar 6 '17 at 3:34

14wml

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Add a comment

1 Answer

1

No. It is not true that =cos()+sin(). Notice that

1=1≠cos()+sin(),

for example consider this at =0.

As a hint for figuring this out, notice that

+=ln(+)

then recall your rules for logarithms to get this to the form (+)ln().

8 0
3 years ago
Identify the terms, like terms, coefficients, and constants in each expression. –5x + 4 – x –1
-Dominant- [34]
-6x+3 u have to add same integers and subtract different integers
6 0
3 years ago
express the numbers eight, fifteen and seventeen in base 2. I have forgotten how to do the base 2 question.
saw5 [17]
The quickest way for converting small numbers like this to binary would probably be to find the closest power of 2, then add/subtract intermediate powers of 2 as needed.

Converting 8 is immediate, since it's already a power of 2:

8=2^3\implies 8_{10}=1000_2

Converting 15 and 17 is also pretty easy if you're familiar with the rules of arithmetic in binary.

15=16-1=2^4-2^0\implies 15_{10}=16_{10}-1_{10}=10000_2-1_2=1111_2

17=16+1=2^4+2^0\implies 17_{10}=10000_2+1_2=10001_2
6 0
3 years ago
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