Question

The volume of a CONE-shaped hole is 75pi ft cubed. If the hole is 9 feet deep, what is the radius of the hole?

Answer 1

Answer:

The radius of hole is 5 feet

Step-by-step explanation:

Depth of conical hole = 9 feet

Let the radius of hole be r

Volume of conical hole =$\frac{1}{3} \pi r^2 h$

So, Volume of conical hole =$\frac{1}{3} \pi \times r^2 \times 9$

We are given that volume of a CONE-shaped hole is 75pi ft cubed.

So,$\frac{1}{3} \pi \times r^2 \times 9=75 \pi$

$\frac{1}{3} \times r^2 \times 9=75$

$r^2=\frac{75 \times 3}{9}$

$r=\sqrt{\frac{75 \times 3}{9}}$

r=5

Hence The radius of hole is 5 feet