-4x = 16 a -64 b 4 c 20 d-4

Sauron [17]

Your answer will be B because since the base is 4 you need to multiply it with something that will divide by 2 and equal 20. so 4x10=40 and 40/2=20 so b is your answer

5 0

3 years ago

Read 2 more answers

Diana worked on her science project for 6

worty [1.4K]

False just do 613 times 134 you will get a larger number

8 0

4 years ago

For the functions f(x) = 2x – 3 and g(x) = 5x + 5, find (f • g)(x).

Nimfa-mama [501]

Answer:

f(g(x)) = 10x + 7

Step-by-step explanation:

(f . g)(x) = f(g(x)) is the composition of the functions f(x) and g(x).

f(g(x)) means that g(x) becomes the input for f.

Now, f(x) = 2x - 3 and g(x) = 5x + 5.

f(g(x)) = f(5x + 5)

= 2((5x + 5) - 3)

= 10x + 10 - 3

= 10x + 7

f(g(x)) = 10x + 7 is the required answer.

5 0

4 years ago

Two airport shuttle trains leave the main station at the same time. Shuttle A returns to the station every 8 minutes. Shuttle B

IgorC [24]

The answer is C. 40 minutes

8 0

4 years ago

A function f has the following verbal description: multiply by 3, add 5, and

STALIN [3.7K]

Regarding the functions in this problem, it is found that:

a) The verbal description of the inverse is: Take the third root, subtract by 5 and divide by 3.

b) The formulas are:

f(x) = (3x + 5)³.

$f^{-1}(x) = \frac{\sqrt[3]{x} - 5}{3}$

c) The compositions result in x, hence they are inverses.

<h3>How to obtain the inverse function?</h3>

The original function is described as follows:

Multiply by 3: 3x.

Add 5: 3x + 5.

Take the third power: (3x + 5)³.

Hence the function is:

y = (3x + 5)³.

To obtain the inverse functions, we exchange x and y and then isolate y, hence:

x = (3y + 5)³

$\sqrt[3]{x} = \sqrt[3]{(3y+5)^3}$

$3y + 5 = \sqrt[3]{x}$

$3y = \sqrt[3]{x} - 5$

$y = \frac{\sqrt[3]{x} - 5}{3}$

$f^{-1}(x) = \frac{\sqrt[3]{x} - 5}{3}$

The verbal description of the inverse is:

Take the third root. sqrt[3](x).

Subtract by 5: sqrt[3](x) - 5.

Divide by 3.

The compositions are given as follows:

$f(f^{-1}(x)) = f\left(\frac{\sqrt[3]{x} - 5}{3}\right) = \left(3\left(\frac{\sqrt[3]{x} - 5}{3}\right + 5)\right)^3 = (\sqrt[3]{x})^3 = x$

$f^{-1}(f(x)) = f^{-1}((3x + 5)^3) = \frac{\sqrt[3]{(3x + 5)^3} - 5}{3} = \frac{3x + 5 - 5}{3} = x$

More can be learned about inverse functions at brainly.com/question/11735394

#SPJ1

4 0

2 years ago