Answer:
The required vector parametric equation is given as:
r(t) = <3cost, 3sint>
For 0 ≤ t ≤ 2π
Step-by-step explanation:
Given that
f(x, y) = <2y, -sin(y)>
Since C is a cirlce centered at the origin (0, 0), with radius r = 3, it takes the form
(x - 0)² + (y - 0)² = r²
Which is
x² + y² = 9
Because
cos²β + sin²β = 1
and we want to find a vector parametric equations r(t) for the circle C that starts at the point (3, 0), we can write
x = 3cosβ
y = 3sinβ
So that
x² + y² = 3²cos²β + 3²sin²β
= 9(cos²β + sin²β) = 9
That is
x² + y² = 9
The vector parametric equation r(t) is therefore given as
r(t) = <x(t), y(t)>
= <3cost, 3sint>
For 0 ≤ t ≤ 2π
Answer:
Step-by-step explanation:
Sin theta = 8/17 and theta is in the second quadrant. Find sin(2theta),cos(2theta),tan(2theta) exactly sin(2theta) cos(2theta) tan(2theta) sin(2theta) would it be 2 x (8/17) cos(2theta) would be 2 x (15/17) tan(2theta) would be 2 x (8/17 divided by 15/17) is this correct?
Answer:
Step-by-step explanation:
sec x( cotx + cos x )= csc x+ 1
1/cos x( cosx/ sinx +cosx) = csc x+ 1
1/cosx ( cosx + sinxcosx/sinx) = csc x+ 1
1/cosx( cosx) ( 1+sinx/sinx) = csc x+ 1
1(1/sinx+1) = csc x+ 1
cscx +1= = csc x+ 1
Answer:
4y6+8y4-2y2-y+10... you start with the one with the highest power first .. end with the one with the least power...
