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Verizon [17]
3 years ago
13

The table shows equivalent ratios for converting from the United States dollar (USD) to the Canadian dollar (CAD). What is the C

anadian dollar equivalent of 25 USD? Conversion Chart USD CAD 5 4.95 7 6.93 8 7.92 11 10.89 ANSWERS: A) 18.00 CAD B) 21.66 CAD C) 24.75 CAD D) 34.65 CAD
Mathematics
2 answers:
Vlada [557]3 years ago
7 0

Answer:

C

Step-by-step explanation:

24.75

Illusion [34]3 years ago
6 0

Answer:

The answer is C

Step-by-step explanation:

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State whether each of the following changes would make a confidence interval wider or narrower.​ (Assume that nothing else​ chan
Hatshy [7]

Answer:

Step-by-step explanation:

The formula for determining confidence interval is expressed as

Confidence interval

= mean ± z × s/ √n

Where

z is the value of the z score

s = standard deviation

n = sample size

a) The 95​% confidence level has a z value of 1.96

The 99​% confidence level has a z value of 2.58

Since 99​% confidence level z value is greater than 95​% confidence level z value, if we input it into the formula, it will result to a higher confidence interval. So changing from a 95​% confidence level to a 99​% confidence level would make a confidence interval wider.

b) The √15 is smaller than the √350. This means that if we make use of the formula, √350 will give a lower confidence interval than that of √15. Therefore, the confidence interval would be narrower changing from a sample size of 15 to a sample size of 350.

c) Applying the formula, a standard deviation of 15 pounds would result to a lower confidence interval than a standard deviation of 20 pounds. Therefore, the confidence interval would be wider changing from a standard deviation of 15 pounds to a standard deviation of 20 pounds.

3 0
3 years ago
Please please help me!!!
Hoochie [10]
4+6+2+2+3+4+6+3=30
14/30 = male
16/30=female
6/30= female junior
6/30= 1/5=20%
Answer: 20%
4 0
3 years ago
Find the greatest common factor: 24y^8 + 6y^6
Marrrta [24]

Find the Greatest Common Factor (GCF)

<u>GCF = 6y^6</u>

Factor out the GCF. (Write the GCF first. Then, in parenthesis divide each term by the GCF.)

6y^6(24y^8/6y^6 + 6y^6/6y^6)

Simplify each term in parenthesis

<u>6y^6(4y^2 + 1)</u>

7 0
3 years ago
A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of
ddd [48]

There are

\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}

ways of pairing up any 2 members from the pool of 2n contestants. Note that

(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)

so that

\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}

4 0
2 years ago
(1/4)^3z-1 =16^z+2*64^z-2<br><br> Z=___<br><br> Please help
wariber [46]

Answer:

Z = 0.198877274

Step-by-step explanation:

(\frac{1}{4})^{3z-1} = 16^z + 2*16^{z-2}\\4^{1-3z} = 4^{2z} + 4^{\frac{1}{2}}*4^{2z-4}\\4^{1-3z} = 4^{2z} + 4^{2z-4+\frac{1}{2}}\\4^{1-3z} = 4^{2z} + 4^{2z-\frac{7}{2}}\\4^{1-3z} = 4^{2z} *(1+ 4^{-\frac{7}{2}})\\4^{1-3z} = 4^{2z} *(1+ 2^{-7})\\4^{1-3z} = 4^{2z} *(1+ \frac{1}{128} )\\4^{1-3z} = 4^{2z} *(\frac{129}{128} )\\Taking\;\; Logarithm\;\; with\;\; base\;\; 4\\Log_4(4^{1-3z}) = Log_4(4^{2z}) + Log_4(\frac{129}{128})\\1-3z = 2z + 0.005613627712 \\5z = 0.994386372\\z = 0.198877274

Hence, the value of Z = 0.198877274

8 0
3 years ago
Read 2 more answers
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