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Leviafan [203]
3 years ago
8

Can u help solve this

Mathematics
1 answer:
aniked [119]3 years ago
4 0

Answer:

 - 5/3

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

    = ( -1 -9)/(4 - -2)

   = (-1-9)/(4+2)

  = -10/6

  - 5/3

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Pls help me. First answer will be marked brainliest
defon
The answer is c
youre welcome vro

5 0
4 years ago
NEED HELP ASAP, WILL GIVE BRAINLIEST
Stella [2.4K]

Given:

The equation of circle is

(x+3)^2+y^2=9

To find:

The polar form of given circle.

Solution:

We have,

(x+3)^2+y^2=9

x^2+2(x)(3)+(3)^2+y^2=9        [\because (a+b)^2=a^2+2ab+b^2]

(x^2+y^2)+6x+9=9

Subtracting 9 from both sides, we get

(x^2+y^2)+6x=0

We know that, x^2+y^2=r^2 and x=r\cos \theta.

r^2+6(r\cos \theta)=0

r(r+6\cos \theta)=0

r=0 and r+6\cos \theta=0

We know that, r is radius it cannot be 0. So,

r+6\cos \theta=0

r=-6\cos \theta

Therefore, the correct option is A.

4 0
3 years ago
A parking lot has ten parking spaces. There are the same number of cars parked in the parking lot as there are empty parking spa
Karolina [17]

Answer:

0.5

Step-by-step explanation:

Total space in the parking lot = 10

number of cars parked = p

number of empty parking spaces = e

There are the same number of cars parked in the parking lot as there are empty parking spaces.

This means,

Number of parked cars = number of empty parking spaces

p = e

If the number of parked cars and number of empty parking spaces = 10

p + e = 10

If p = 5

Then,

p + e = 10

5 + 5 = 10

Write a decimal to show the part of the parking lot that has empty parking spaces.

Empty parking space/total parking space

= 5/10

= 1/2

= 0.5

part of the parking lot that has empty parking spaces = 0.5

8 0
3 years ago
Answer asap please
Oduvanchick [21]

Answer:

(0,1) and (-2,9)

Step-by-step explanation:

A point (x,y) lies on the graph of f(x) = (\frac{1}{3} )^{x} if it satisfies the condition y = (\frac{1}{3} )^{x}

<h3>(0,1):</h3>

        x = 0 and y = 1.

This point satisfies the required condition as

        (\frac{1}{3} )^{0} = 1

Hence, this point <u>is</u> on the graph of f(x) = (\frac{1}{3} )^{x}

<h3>(3,27):</h3>

        x = 3 and y = 27.

This point doesn't satisfy the required condition as

        (\frac{1}{3} )^{3} = \frac{1}{27} ≠ 27

Hence, this point i<u>s not</u> on the graph of f(x) = (\frac{1}{3} )^{x}

<h3>(-2,9):</h3>

        x = -2 and y = 9.

This point satisfies the required condition as

        (\frac{1}{3} )^{-2} = 3^{2} = 9

Hence, this point <u>is</u> on the graph of f(x) = (\frac{1}{3} )^{x}

<h3>(-1,-\frac{1}{3}):</h3>

        x = -1 and y = -\frac{1}{3}.

This point satisfies the required condition as

        y = (\frac{1}{3} )^{-1} = 3^{1} = 3 ≠ -\frac{1}{3}

Hence, this point <u>is not</u> on the graph of f(x) = (\frac{1}{3} )^{x}

7 0
3 years ago
The equation below describes a circle. What are the coordinates of the center of the circle
hjlf
So the coordinates of the center of the circle will be (-5,-7)

hope you know formula for equation of a circle 
6 0
3 years ago
Read 2 more answers
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