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Doss [256]
3 years ago
11

Amber the giant panda can eat at least 2.5 kilograms of

Mathematics
1 answer:
geniusboy [140]3 years ago
8 0

Answer:

i think 6 hours so sry if i am wrong good luck

Step-by-step explanation:

You might be interested in
Orange M&M’s: The M&M’s web site says that 20% of milk chocolate M&M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
3 years ago
HELP MEE!!! Make sure to simply please
givi [52]

Answer:

YOUR CAMERA IS BAD I CANT SEE ANYTHING

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the missing side lengths
Mashcka [7]

Answer:

y = 9√3

x = 18

Step-by-step explanation:

taking 30 as reference angle

b = y

p = 9

h = x

so

tan30 = p/b

1/√3 = 9/b

or, b = 9√3

so

h^2 = p^2 + b^2\\x^2 = 9^2 + y^2\\or, x^2 = 81 + (9\sqrt{3} )^2\\or, x^2 = 81 + 243\\or, x ^2 = 324\\or, x =\sqrt{324} \\\\so x = 18

7 0
3 years ago
One sixth of fifty four
marissa [1.9K]
1/6 x 54 = 9
Hope this helps ;)
8 0
3 years ago
Jen measured the growth of a sunflower in one week it grew 2 and 1 half in
Pie
So you basically add the amount it grew each week. So week one is 2 and 1/2, week two is 2 and 3/4 and week three is 3 and 1/4. to make things simpler, add week two and three which gets you 6inches, then add week one, to get 8 and a half inches.
8 0
3 years ago
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