I hope this helps you
1)
y=6
x^2+6^2=25
x^2=25-36
x^2= -9
x^2=i^2.9
x=3i there's no real solution
2)
x^2+(2x-2)^2=25
x^2+4x^2-8x+4=25
5x^2-8x=21
5x^2-8x-21=0
5x +7
x -3
(5x+7)(x-3)=0
x= -7/5
x=3
Answer:
5.8
Step-by-step explanation:
Y e s .
Using the Distance formula and all.
Answer:
<h2>a₈ = 1</h2>
Step-by-step explanation:
![\text{Put}\ n=8\ \text{to the sequence}\ a_n=25-3n:\\\\a_8=25-3(8)=25-24=1](https://tex.z-dn.net/?f=%5Ctext%7BPut%7D%5C%20n%3D8%5C%20%5Ctext%7Bto%20the%20sequence%7D%5C%20a_n%3D25-3n%3A%5C%5C%5C%5Ca_8%3D25-3%288%29%3D25-24%3D1)
The inside angles of a triangle equal 180 degrees
so
(2x -2) + (x+6) + x = 180
combine like terms
4x + 4 = 180
subtract 4 from both sides
4x = 176
divide both sides by 4
x = 44
Now, wherever is says x, plug in 44
(x+6)
44 + 6
angle B is 50
2x - 2
2(44) -2
88-2
Angle A is 86
and the last angle is just 44
To check:
angle a + angle b + angle c =?= 180
86 + 50 + 44 =?= 180
180 = 180
Hope this helps
Answer:
See explanation
Step-by-step explanation:
One vertex is at point (2,3).
Go 1 unit to the left and 5 units up, then the second vertex will be at the point (1,8).
Go 5 units to the right and 1 unit up, then the third vertex will be at point (6,9).
Go 1 unit to the right and 5 units down, then the fourth vertex will be at point (7,4).
Go 5 units to the left and 1 unit down to get into the vertex (2,3).
Since you always move one unit in one direction and 5 units in another direction, obtained quadrilateral will be a square.
See attached diagram for details.